Question

1)Beo+h2o= 2)cao+h2o= 3)cao+h2o= 4)na2o+h2o=

Answer 1

1) Эта реакция невозможна. Бериллий не взаимодействует с водой.
2) CaO + H₂O = Ca(OH)₂
3) Тоже самое.
4) Na₂O+H₂O=2NaOH

Answer 2

1) BeO + H2O:

When beryllium oxide (BeO) reacts with water (H2O), it undergoes a hydrolysis reaction. The reaction can be represented as follows:

BeO + H2O → Be(OH)2

In this reaction, beryllium oxide reacts with water to form beryllium hydroxide (Be(OH)2). Beryllium hydroxide is an amphoteric compound, which means it can react both as an acid and a base.

2) CaO + H2O:

When calcium oxide (CaO), also known as quicklime, reacts with water (H2O), it undergoes a highly exothermic reaction known as slaking of lime. The reaction can be represented as follows:

CaO + H2O → Ca(OH)2

In this reaction, calcium oxide reacts with water to form calcium hydroxide (Ca(OH)2), also known as slaked lime. This reaction is highly exothermic, meaning it releases a significant amount of heat. Calcium hydroxide is a white, crystalline solid that is slightly soluble in water.

3) Ca(OH)2 + H2O:

When calcium hydroxide (Ca(OH)2) reacts with water (H2O), it undergoes a process called hydration. The reaction can be represented as follows:

Ca(OH)2 + H2O → Ca(OH)2 · 2H2O

In this reaction, calcium hydroxide reacts with water to form a hydrated form of calcium hydroxide, which is represented as Ca(OH)2 · 2H2O. This hydrated form of calcium hydroxide is commonly known as slaked lime.

4) Na2O + H2O:

When sodium oxide (Na2O) reacts with water (H2O), it undergoes a hydrolysis reaction. The reaction can be represented as follows:

Na2O + H2O → 2NaOH

In this reaction, sodium oxide reacts with water to form sodium hydroxide (NaOH), also known as caustic soda. Sodium hydroxide is a strong base and is highly soluble in water.