Question

Определить число молекул содержащихся в 5,1 г NH3

Answer 1

M = 5.1 (г)

M(NH3) = 14+3*1=17 (г/моль)
n=m/M = 5.1/17 = 0.3 (моль)
N= Na*n, где Na - число Авогадро = 6,02*10^23 (молекул/моль)
N = 6.02*10^23* 0.3 = 1.806*10^23 (молекул)

Answer 2

Calculating the Number of Molecules in 5.1g of NH3

To determine the number of molecules in 5.1g of NH3, we can use the following steps:

1. Calculate the number of moles of NH3: - The molar mass of NH3 (ammonia) is approximately 17.031 g/mol. - Using the formula: \[ \text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \] we can calculate the number of moles of NH3 in 5.1g.

2. Use Avogadro's number to find the number of molecules: - Avogadro's number is approximately \(6.022 \times 10^{23}\) molecules/mol. - We can use this value to convert the number of moles of NH3 to the number of molecules.

Let's proceed with the calculations.

Calculation

1. Calculate the number of moles of NH3: - Using the molar mass of NH3: \[ \text{moles} = \frac{5.1 \, \text{g}}{17.031 \, \text{g/mol}} \approx 0.299 \, \text{moles} \, (\text{rounded to three decimal places}) \]

2. Use Avogadro's number to find the number of molecules: - Using Avogadro's number: \[ \text{Number of molecules} = \text{moles} \times 6.022 \times 10^{23} \approx 0.299 \, \text{moles} \times 6.022 \times 10^{23} \approx 1.80 \times 10^{23} \, \text{molecules} \]

Therefore, there are approximately 1.80 x 10^23 molecules in 5.1g of NH3.

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