Question

Чему равна масса оксида меди (2) который вступает в реакцию с 490 граммами 10 процентного раствора серной кислоты

Answer 1

Масса оксида меди=40г

Answer 2

Calculating the Mass of Copper(II) Oxide Reacting with Sulfuric Acid

To calculate the mass of copper(II) oxide (CuO) that reacts with 490 grams of a 10% sulfuric acid solution, we can use the stoichiometry of the reaction between copper(II) oxide and sulfuric acid.

The balanced chemical equation for the reaction is: CuO + H2SO4 → CuSO4 + H2O

From the balanced equation, we can see that 1 mole of CuO reacts with 1 mole of H2SO4.

Calculating the Molar Mass of Sulfuric Acid

The molar mass of sulfuric acid (H2SO4) is calculated as follows: - Molar mass of H2SO4 = 2(1.008) + 32.06 + 4(16.00) = 98.08 g/mol.

Calculating the Molar Mass of Copper(II) Oxide

The molar mass of copper(II) oxide (CuO) is calculated as follows: - Molar mass of CuO = 63.55 + 16.00 = 79.55 g/mol.

Calculating the Amount of Sulfuric Acid in the Solution

The amount of sulfuric acid in the 10% solution can be calculated using the formula: - Amount of H2SO4 = (10/100) * 490 g = 49 g.

Calculating the Amount of Copper(II) Oxide

To find the amount of copper(II) oxide that reacts with 49 grams of sulfuric acid, we can use the molar ratio between CuO and H2SO4 from the balanced chemical equation.

Since 1 mole of CuO reacts with 1 mole of H2SO4, the amount of CuO can be calculated using the formula: - Amount of CuO = (49 g / molar mass of H2SO4) * molar mass of CuO - Amount of CuO = (49 g / 98.08 g/mol) * 79.55 g/mol - Amount of CuO ≈ 39.78 g

Therefore, the mass of copper(II) oxide (CuO) that reacts with 490 grams of a 10% sulfuric acid solution is approximately 39.78 grams.