Question

AlCl3+Ca(OH)2=; Na2SiO3+HCl=;BaCl2+Na2SO4=;Cu(NO3)2+KOH=;срочноооооо!!!!

Answer 1

2AlCl3+3CA(OH)2=2 Al(OH)3+3CACl2
Na2SiO3+2HCl=H2SiO3+2NaCl
BaCl2+Na2SO4=BaSO4+2NaCl
Cu(NO3)2+KOH=Cu(OH)2+2KNO3

Answer 2

AlCl3 + Ca(OH)2 = ?

The reaction between aluminum chloride (AlCl3) and calcium hydroxide (Ca(OH)2) is a double displacement reaction. It can be represented by the following balanced chemical equation:

2AlCl3 + 3Ca(OH)2 → 2Al(OH)3 + 3CaCl2

In this reaction, aluminum chloride reacts with calcium hydroxide to form aluminum hydroxide and calcium chloride. The balanced equation shows that 2 moles of aluminum chloride react with 3 moles of calcium hydroxide to produce 2 moles of aluminum hydroxide and 3 moles of calcium chloride.

Na2SiO3 + HCl = ?

The reaction between sodium silicate (Na2SiO3) and hydrochloric acid (HCl) is an acid-base reaction. It can be represented by the following balanced chemical equation:

Na2SiO3 + 2HCl → H2SiO3 + 2NaCl

In this reaction, sodium silicate reacts with hydrochloric acid to form silicic acid and sodium chloride. The balanced equation shows that 1 mole of sodium silicate reacts with 2 moles of hydrochloric acid to produce 1 mole of silicic acid and 2 moles of sodium chloride.

BaCl2 + Na2SO4 = ?

The reaction between barium chloride (BaCl2) and sodium sulfate (Na2SO4) is a double displacement reaction. It can be represented by the following balanced chemical equation:

BaCl2 + Na2SO4 → BaSO4 + 2NaCl

In this reaction, barium chloride reacts with sodium sulfate to form barium sulfate and sodium chloride. The balanced equation shows that 1 mole of barium chloride reacts with 1 mole of sodium sulfate to produce 1 mole of barium sulfate and 2 moles of sodium chloride.

Cu(NO3)2 + KOH = ?

The reaction between copper(II) nitrate (Cu(NO3)2) and potassium hydroxide (KOH) is a double displacement reaction. It can be represented by the following balanced chemical equation:

Cu(NO3)2 + 2KOH → Cu(OH)2 + 2KNO3

In this reaction, copper(II) nitrate reacts with potassium hydroxide to form copper(II) hydroxide and potassium nitrate. The balanced equation shows that 1 mole of copper(II) nitrate reacts with 2 moles of potassium hydroxide to produce 1 mole of copper(II) hydroxide and 2 moles of potassium nitrate.

I hope this helps! Let me know if you have any further questions.