Question

Химия срочно 4.Какой объём оксида углерода ( IV ) требуется пропустить через гидроксид кальция для получения карбоната кальция массой 250 г.?

Answer 1

                V-?      250г
Ca(OH)2+CO2=CaCO3+H2O
               22,4л   100г
V(CO2)=22,4*100/250=56(л)
Ответ: 56л

Answer 2

Calculating the Volume of Carbon Dioxide (IV) Needed to Produce Calcium Carbonate

To calculate the volume of carbon dioxide (IV) needed to produce calcium carbonate with a mass of 250 g, we can use the following chemical equation:

Ca(OH)2 + CO2 → CaCO3 + H2O

From the equation, we can see that 1 mole of calcium carbonate is produced for every mole of carbon dioxide (IV) reacted.

Given that the molar mass of calcium carbonate (CaCO3) is approximately 100.09 g/mol, we can calculate the number of moles of calcium carbonate produced from the given mass.

Calculation Steps:

1. Calculate the number of moles of calcium carbonate: - Molar mass of CaCO3 = 100.09 g/mol - Given mass of CaCO3 = 250 g - Number of moles = Given mass / Molar mass - Number of moles = 250 g / 100.09 g/mol

2. Calculate the volume of carbon dioxide (IV) needed: - Since 1 mole of CaCO3 is produced for every mole of CO2 reacted, the number of moles of CO2 needed is the same as the number of moles of CaCO3.

3. Convert the number of moles to volume using the ideal gas law: - PV = nRT - Where: - P = pressure (assume standard pressure, 1 atm) - V = volume - n = number of moles - R = ideal gas constant (0.0821 L·atm/(K·mol)) - T = temperature (assume standard temperature, 273 K)

4. Rearrange the ideal gas law to solve for V (volume): - V = nRT / P

Result:

The volume of carbon dioxide (IV) needed to produce calcium carbonate with a mass of 250 g can be calculated using the steps above.

Let's proceed with the calculations.