Question

ZnCl2+HОН ионное уравнение

Answer 1

ZnCl2 + НОН⇄ ZnОНCl + НCl б) ZnОН+ + НОН ⇄ Zn(ОН)2 + Н+

Answer 2

Ionic Equation for ZnCl2 + HОН

The ionic equation for the reaction between ZnCl2 and HОН can be represented as follows:

ZnCl2 + 2NaOH → Zn(OH)2 + 2NaCl

This can be further broken down into ionic species as:

Zn2+ + 2Cl- + 2Na+ + 2OH- → Zn(OH)2 + 2Na+ + 2Cl-

The balanced ionic equation for the reaction between ZnCl2 and HОН is:

Zn2+ + 2OH- → Zn(OH)2

This equation represents the dissociation of ZnCl2 in the presence of NaOH to form Zn(OH)2 and NaCl.

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