Question

Молекулярная масса галогенида одновалентного металла в 2,228 раза больше, чем молекулярная масса другого галогенида этого же металла, а атомные массы галогенов, которые входят в состав солей, относятся как 1: 3,58. Определите качественный состав галогенидов.

Answer 1

1) Общая ф-ла галогенидов в соот-ии с условием - MeHal;

2) данное соот-ие атомных масс галогенов (1:3.58) харак-но для пары Cl-I (35.5/127 = 1/3.58), т.е. галогенид с большей М - MeI, с меньшей - MeCl;

3) молярная масса металла - М и в соот-ии с условием пол-м (М+35.5)*2.228 = М+127, откуда М = 39 г/моль (металл - калий K);

4) т.о. были взяты хлорид и иодид калия KCl и KI.

Answer 2

Qualitative Composition of Halides

To determine the qualitative composition of the halides, we need to analyze the given information about the molecular masses and atomic masses of the halogens.

According to the information provided, the molecular mass of the halide of a monovalent metal is 2.228 times greater than the molecular mass of another halide of the same metal. Additionally, the atomic masses of the halogens that make up the salts are in a ratio of 1:3.58.

Let's assume the molecular mass of the halide with the lower molecular mass is "x." Therefore, the molecular mass of the other halide would be 2.228x.

Now, let's consider the atomic masses of the halogens. Since the ratio of the atomic masses is 1:3.58, we can assign the atomic mass of the halogen in the halide with the lower molecular mass as "y." Consequently, the atomic mass of the halogen in the halide with the higher molecular mass would be 3.58y.

To determine the qualitative composition of the halides, we need to find the ratio of the metal to the halogen in each halide. We can do this by dividing the molecular mass of each halide by the atomic mass of the respective halogen.

Let's calculate the ratios:

For the halide with the lower molecular mass: - Metal to halogen ratio = x/y

For the halide with the higher molecular mass: - Metal to halogen ratio = 2.228x/3.58y

Since the ratios of the metal to the halogen in both halides are equal, we can equate the two ratios and solve for x and y.

x/y = 2.228x/3.58y

Simplifying the equation, we get:

3.58x = 2.228x

x = 0

This implies that the molecular mass of the halide with the lower molecular mass is zero, which is not possible. Therefore, there seems to be an inconsistency in the given information.

Without further clarification or correction of the information, it is not possible to determine the qualitative composition of the halides based on the provided data.

Please provide additional information or clarify the given data to assist you further.