Question

Определите массу меди, которая образуется при взаимодействии железа с раствором хлорида меди (II) массой 25 г.

Answer 1

  0,19моль              x моль
CuCl2+Fe=FeCl2+ Cu
1моль                  1моль
Нах-м кол-во в-ва хлорида меди =m/M=25/135=0.19моль
нах-м кол-во в-ва Cu=x=0.19моль
нах-м массу меди = кол-во в-ва *М=0,19*64=12г

Answer 2

Calculating the Mass of Copper Formed

To determine the mass of copper formed when iron reacts with a solution of copper (II) chloride, we can use the stoichiometry of the reaction to calculate the mass of copper produced.

The balanced chemical equation for the reaction between iron and copper (II) chloride is:

Fe + CuCl2 → FeCl2 + Cu

From the balanced chemical equation, we can see that 1 mole of iron reacts with 1 mole of copper (II) chloride to produce 1 mole of copper.

Given that the mass of iron is 25 g, we need to calculate the mass of copper formed.

Calculation

1. Calculate the molar mass of copper (Cu) and copper (II) chloride (CuCl2). - The molar mass of copper (Cu) is approximately 63.55 g/mol. - The molar mass of copper (II) chloride (CuCl2) is approximately 134.45 g/mol.

2. Use the molar ratio from the balanced chemical equation to calculate the moles of copper formed. - The molar ratio of Fe to Cu is 1:1.

3. Calculate the moles of copper formed. - Moles of Fe = Mass of Fe / Molar mass of Fe - Moles of Cu = Moles of Fe (from the balanced equation)

4. Finally, calculate the mass of copper formed using the moles of copper and the molar mass of copper.

Conclusion

By following these steps, you can calculate the mass of copper formed when iron reacts with a solution of copper (II) chloride.