Question

Определить массу хлорида алюминия образуещегося при взаимодействии 2,7грамм алюминия с хлором

Answer 1

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Answer 2

Calculating the Mass of Aluminum Chloride Formed

To determine the mass of aluminum chloride formed when 2.7 grams of aluminum reacts with chlorine, we can use the balanced chemical equation for the reaction between aluminum and chlorine. The balanced chemical equation for the reaction is:

2 Al + 3 Cl2 → 2 AlCl3

According to the balanced chemical equation, 2 moles of aluminum react with 3 moles of chlorine to produce 2 moles of aluminum chloride.

To calculate the mass of aluminum chloride formed, we can use the molar mass of aluminum and chlorine to find the moles of each reactant and then use the mole ratio from the balanced chemical equation to determine the moles of aluminum chloride produced.

Calculation Steps

1. Calculate the moles of aluminum: - Given mass of aluminum = 2.7 grams - Molar mass of aluminum (Al) = 26.98 g/mol

Moles of aluminum = Given mass of aluminum / Molar mass of aluminum

2. Calculate the moles of chlorine: - Since the molar mass of chlorine is not provided in the search results, I will use the standard molar mass of chlorine, which is 35.45 g/mol.

Moles of chlorine = Moles of aluminum * (3 moles of Cl2 / 2 moles of Al)

3. Calculate the moles of aluminum chloride formed: - According to the balanced chemical equation, 2 moles of aluminum chloride are produced for every 2 moles of aluminum.

Moles of aluminum chloride = Moles of aluminum * (2 moles of AlCl3 / 2 moles of Al)

4. Calculate the mass of aluminum chloride formed: - Molar mass of aluminum chloride (AlCl3) = 133.34 g/mol

Mass of aluminum chloride formed = Moles of aluminum chloride * Molar mass of aluminum chloride

Let's perform the calculations using the given information and the standard molar mass of chlorine.

Calculation

1. Moles of aluminum: - Moles of aluminum = 2.7 g / 26.98 g/mol = 0.1001 moles

2. Moles of chlorine: - Moles of chlorine = 0.1001 moles * (3 moles of Cl2 / 2 moles of Al) = 0.1502 moles

3. Moles of aluminum chloride formed: - Moles of aluminum chloride = 0.1001 moles * (2 moles of AlCl3 / 2 moles of Al) = 0.1001 moles

4. Mass of aluminum chloride formed: - Mass of aluminum chloride formed = 0.1001 moles * 133.34 g/mol = 13.35 grams

The mass of aluminum chloride formed when 2.7 grams of aluminum reacts with chlorine is approximately 13.35 grams.