Question

нужно расставить коэфициенты методом электронного баланса1)K2Cr2O7+NaI+H2SO4---->Cr2(SO4)3+I2+Na2SO4+K2SO4+H2O2) KMnO4+(NH4)Br+H2SO4--->MnSO4+Br2+K2SO4+(NH4)2SO4+H2O

Answer 1

K2Cr2O7+6 NaI + 7H2SO4 = Cr2(SO4)3 + 3I2 + 3Na2SO4 + K2SO4 + 7H2O 

 

2 KMnO4 + 10 (NH4)Br + 8 H2SO4 = 2 MnSO4 + 5 Br2 + K2SO4 + 5 (NH4)2SO4 + 8 H2O 

 

если нужны степени окисления,переходы электронов,окисслители и восстановители, то напиши. я расспишу) 

Answer 2

Balancing Chemical Equations

To balance the chemical equations provided using the method of electronic balancing, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

1) K2Cr2O7 + NaI + H2SO4 -> Cr2(SO4)3 + I2 + Na2SO4 + K2SO4 + H2O

To balance this equation, we can follow these steps:

Step 1: Balance the atoms other than hydrogen and oxygen. - Start by balancing the atoms that appear in only one compound on each side of the equation. - In this case, we can start with the iodine (I) atoms. There are two iodine atoms on the left side (NaI), so we need two iodine atoms on the right side (I2). - The equation now becomes: K2Cr2O7 + NaI + H2SO4 -> Cr2(SO4)3 + 2I2 + Na2SO4 + K2SO4 + H2O

Step 2: Balance the oxygen atoms. - Count the number of oxygen atoms on each side of the equation. - On the left side, there are seven oxygen atoms in K2Cr2O7 and one oxygen atom in H2SO4, giving a total of eight oxygen atoms. - On the right side, there are three oxygen atoms in Cr2(SO4)3 and one oxygen atom in H2O, giving a total of four oxygen atoms. - To balance the oxygen atoms, we need to add four more oxygen atoms to the right side. - We can achieve this by adding four water molecules (H2O) to the right side of the equation. - The equation now becomes: K2Cr2O7 + NaI + H2SO4 -> Cr2(SO4)3 + 2I2 + Na2SO4 + K2SO4 + 4H2O

Step 3: Balance the hydrogen atoms. - Count the number of hydrogen atoms on each side of the equation. - On the left side, there are four hydrogen atoms in H2SO4. - On the right side, there are eight hydrogen atoms in 4H2O. - To balance the hydrogen atoms, we need to add four more hydrogen atoms to the left side. - We can achieve this by adding four hydrogen ions (H+) to the left side of the equation. - The equation now becomes: K2Cr2O7 + NaI + 4H+ + H2SO4 -> Cr2(SO4)3 + 2I2 + Na2SO4 + K2SO4 + 4H2O

Step 4: Balance the potassium atoms. - Count the number of potassium atoms on each side of the equation. - On the left side, there are two potassium atoms in K2Cr2O7 and two potassium atoms in K2SO4, giving a total of four potassium atoms. - On the right side, there are two potassium atoms in K2SO4. - The potassium atoms are already balanced.

Step 5: Balance the sodium atoms. - Count the number of sodium atoms on each side of the equation. - On the left side, there is one sodium atom in NaI and two sodium atoms in Na2SO4, giving a total of three sodium atoms. - On the right side, there are no sodium atoms. - To balance the sodium atoms, we need to add three sodium ions (Na+) to the right side of the equation. - The equation now becomes: K2Cr2O7 + NaI + 4H+ + H2SO4 -> Cr2(SO4)3 + 2I2 + 3Na+ + K2SO4 + 4H2O

Step 6: Balance the chromium atoms. - Count the number of chromium atoms on each side of the equation. - On the left side, there are two chromium atoms in K2Cr2O7. - On the right side, there are two chromium atoms in Cr2(SO4)3. - The chromium atoms are already balanced.

Step 7: Balance the sulfur atoms. - Count the number of sulfur atoms on each side of the equation. - On the left side, there is one sulfur atom in H2SO4. - On the right side, there are three sulfur atoms in Cr2(SO4)3 and one sulfur atom in Na2SO4, giving a total of four sulfur atoms. - To balance the sulfur atoms, we need to add three more sulfur atoms to the left side. - We can achieve this by adding three sulfuric acid molecules (H2SO4) to the left side of the equation. - The equation now becomes: K2Cr2O7 + NaI + 4H+ + 3H2SO4 -> Cr2(SO4)3 + 2I2 + 3Na+ + K2SO4 + 4H2O

Now, the equation is balanced: K2Cr2O7 + NaI + 4H+ + 3H2SO4 -> Cr2(SO4)3 + 2I2 + 3Na+ + K2SO4 + 4H2O

2) KMnO4 + (NH4)Br + H2SO4 -> MnSO4 + Br2 + K2SO4 + (NH4)2SO4 + H2O

To balance this equation, we can follow similar steps:

Step 1: Balance the atoms other than hydrogen and oxygen. - Start by balancing the atoms that appear in only one compound on each side of the equation. - In this case, we can start with the bromine (Br) atoms. There is one bromine atom on the left side ((NH4)Br), so we need one bromine atom on the right side (Br2). - The equation now becomes: KMnO4 + (NH4)Br + H2SO4 -> MnSO4 + Br2 + K2SO4 + (NH4)2SO4 + H2O

Step 2: Balance the oxygen atoms. - Count the number of oxygen atoms on each side of the equation. - On the left side, there four oxygen atoms in KMnO4 and one oxygen atom in H2SO4, giving a total of five oxygen atoms. - On the right side, there four oxygen atoms in MnSO4 and two oxygen atoms in H2O, giving a total of six oxygen atoms. - To balance the oxygen atoms, we need to add one more oxygen atom to the left side. - We can achieve this by adding one water molecule (H2O) to the left side of the equation. - The equation now becomes: KMnO4 + (NH4)Br + H2SO4 + H2O -> MnSO4 + Br2 + K2SO4 + (NH4)2SO4 + H2O

Step 3: Balance the hydrogen atoms. - Count the number of hydrogen atoms on each side of the equation. - On the left side, there are four hydrogen atoms in (NH4)Br and two hydrogen atoms in H2SO4, giving a total of six hydrogen atoms. - On the right side, there are four hydrogen atoms in (NH4)2SO4 and two hydrogen atoms in H2O, giving a total of six hydrogen atoms. - The hydrogen atoms are already balanced.

Step 4: Balance the potassium atoms. - Count the number of potassium atoms on each side of the equation. - On the left side, there is one potassium atom in KMnO4 and two potassium atoms in K2SO4, giving a total of three potassium atoms. - On the right side, there are two potassium atoms in K2SO4. - The potassium atoms are already balanced.

Step 5: Balance the ammonium atoms. - Count the number of ammonium atoms on each side of the equation. - On the left side, there is one ammonium ion ((NH4)+) in (NH4)Br and two ammonium ions ((NH4)+) in (NH4)2SO4, giving a total of three ammonium ions. - On the right side, there are no ammonium ions. - To balance the ammonium ions, we need to add three ammonium ions ((NH4)+) to the right side of the equation. - The equation now becomes: KMnO4 + (NH4)Br + H2SO4 + H2O -> MnSO4 + Br2 + K2SO4 + 3(NH4)2SO4 + H2O

Step 6: Balance the manganese atoms. - Count the number of manganese atoms on each side of the equation. - On the left side, there is one manganese atom in KMnO4. - On the right side, there is one manganese atom in MnSO4. - The manganese atoms are already balanced.

Step 7: Balance the sulfur atoms. - Count the number of sulfur atoms on each side of the equation. - On the left side, there is one sulfur atom in H2SO4. - On the right side, there is one sulfur atom in MnSO4 and four sulfur atoms in (NH4)2SO4, giving a total of five sulfur atoms. - To balance the sulfur atoms, we need to add four more sulfur atoms to the left side. - We can achieve this by adding four sulfuric acid molecules (H2SO4) to the left side of the equation. - The equation now becomes: KMnO4 + (NH4)Br + 4H2SO4 + H2O -> MnSO4 + Br2 + K2

Answer 3

Balancing Chemical Equations

To balance the chemical equations using the method of electronic balance, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance the given equations step by step:

1) K2Cr2O7 + NaI + H2SO4 → Cr2(SO4)3 + I2 + Na2SO4 + K2SO4 + H2O

To balance this equation, we can follow these steps:

Step 1: Balance the atoms other than hydrogen and oxygen. - The equation has two potassium (K) atoms on the left side and four potassium (K) atoms on the right side. To balance the potassium atoms, we can put a coefficient of 2 in front of K2Cr2O7 on the left side. - The equation now becomes: 2K2Cr2O7 + NaI + H2SO4 → Cr2(SO4)3 + I2 + Na2SO4 + K2SO4 + H2O

Step 2: Balance the oxygen atoms. - The equation has 14 oxygen (O) atoms on the left side and 14 oxygen (O) atoms on the right side. The oxygen atoms are already balanced.

Step 3: Balance the hydrogen atoms. - The equation has 8 hydrogen (H) atoms on the left side and 2 hydrogen (H) atoms on the right side. To balance the hydrogen atoms, we can put a coefficient of 4 in front of H2O on the right side. - The equation now becomes: 2K2Cr2O7 + NaI + H2SO4 → Cr2(SO4)3 + I2 + Na2SO4 + K2SO4 + 4H2O

Step 4: Balance the remaining atoms. - The equation has 2 chromium (Cr) atoms on the left side and 2 chromium (Cr) atoms on the right side. The chromium atoms are already balanced. - The equation has 7 sulfur (S) atoms on the left side and 7 sulfur (S) atoms on the right side. The sulfur atoms are already balanced. - The equation has 2 iodine (I) atoms on the left side and 2 iodine (I) atoms on the right side. The iodine atoms are already balanced. - The equation has 2 sodium (Na) atoms on the left side and 2 sodium (Na) atoms on the right side. The sodium atoms are already balanced. - The equation has 2 potassium (K) atoms on the left side and 2 potassium (K) atoms on the right side. The potassium atoms are already balanced.

The balanced equation is: 2K2Cr2O7 + 10NaI + 8H2SO4 → 2Cr2(SO4)3 + 7I2 + 4Na2SO4 + K2SO4 + 4H2O

2) KMnO4 + (NH4)Br + H2SO4 → MnSO4 + Br2 + K2SO4 + (NH4)2SO4 + H2O

To balance this equation, we can follow these steps:

Step 1: Balance the atoms other than hydrogen and oxygen. - The equation has one potassium (K) atom on the left side and two potassium (K) atoms on the right side. To balance the potassium atoms, we can put a coefficient of 2 in front of K2SO4 on the right side. - The equation now becomes: KMnO4 + (NH4)Br + H2SO4 → MnSO4 + Br2 + K2SO4 + (NH4)2SO4 + H2O

Step 2: Balance the oxygen atoms. - The equation has 4 oxygen (O) atoms on the left side and 4 oxygen (O) atoms on the right side. The oxygen atoms are already balanced.

Step 3: Balance the hydrogen atoms. - The equation has 8 hydrogen (