Question

Получение CuCl 8 реакций пожалуйста

Answer 1

Cu2O + 2HCl (разб.) = 2CuCl↓ + H2O
2Cu + 2HCl(г) = 2CuCl + H2
Cu2S + Cl2 = 2CuCl + S
Cu + Cl2(влажн. ) = CuCl2
2Cu + 4HCl(разб. ) + O2 = 2CuCl2 + 2H2O
Cu2CO3(OH)2 + 4NH4Cl(конц. ) = 2CuCl2 + CO2↑ + 3H2O + 4NH3↑(кип. )
CuS + 2FeCl3(разб. ) = CuCl2 + 2FeCl2 + S↓
Cu2CO3(OH)2 + 4HCl(разб. ) = 2CuCl2 + CO2↑ + 3H2O

Answer 2

Obtaining CuCl2 through Reactions

To obtain CuCl2, also known as copper(II) chloride, several methods can be employed. One common method involves the reaction between copper metal and hydrochloric acid. Here's a detailed explanation of the reaction:

Reaction: The reaction between copper metal (Cu) and hydrochloric acid (HCl) results in the formation of copper(II) chloride (CuCl2) and hydrogen gas (H2).

The balanced chemical equation for this reaction is: ``` Cu + 2HCl → CuCl2 + H2 ``` This reaction can be carried out by adding copper metal to hydrochloric acid in a suitable reaction vessel.

Another method for obtaining copper(II) chloride involves the reaction between copper(II) oxide and hydrochloric acid. Here's the detailed explanation of this reaction:

Reaction: The reaction between copper(II) oxide (CuO) and hydrochloric acid (HCl) results in the formation of copper(II) chloride (CuCl2) and water (H2O).

The balanced chemical equation for this reaction is: ``` CuO + 2HCl → CuCl2 + H2O ``` This reaction can be carried out by adding copper(II) oxide to hydrochloric acid in a suitable reaction vessel.

These are the two common methods for obtaining copper(II) chloride through chemical reactions.