Question

Фосфат кальция прокалили с углем в присутствии речного песка. Образовавшееся простое вещество прореагировало с избытком хлора. Полученный продукт внесли в избыток гидроксида калия. На образовавшийся раствор подействовали известковой водой. Запишите уравнения реакций

Answer 1

1) Ca3(PO4)2 + 5C + 3SiO2 = 2P + 5CO + 3CaSiO3;

2) 2P + 5Cl2 = 2PCl5;

3) PCl5 + 8KOH = K3PO4 + 5KCl + 4H2O;

4) 2K3PO4 + 3Ca(OH)2 = Ca3(PO4)2 + 6KOH.

Answer 2

Formation of Calcium Phosphate

When calcium phosphate is heated with coal in the presence of river sand, a simple substance is formed. This simple substance then reacts with an excess of chlorine. The resulting product is then treated with an excess of potassium hydroxide. Finally, the resulting solution is reacted with lime water (calcium hydroxide solution).

The reactions can be represented by the following equations:

1. Formation of Simple Substance: - Calcium phosphate + Coal + River sand → Simple substance

2. Reaction with Excess Chlorine: - Simple substance + Excess chlorine → Product

3. Reaction with Excess Potassium Hydroxide: - Product + Excess potassium hydroxide → Solution

4. Reaction with Lime Water: - Solution + Lime water (Calcium hydroxide solution) → Final product

Please note that the specific chemical formulas and balanced equations cannot be provided without more information about the reactants and products involved in each step.