Вопрос задан 18.02.2019 в 16:57. Предмет Химия. Спрашивает Иванов Рёма.

Помоготе расставить коэффициенты в уравнениях хим. реакций и указать тип каждой реакции. И

объясните как это делать. СРОЧНО!!!!!! H2O+Na--------H2 CO2+CaO-------CaCO3 KOH+HBr--------H2O Al+HCl--------AlCl3+H2 KClO3-------KCl+O2
0 0
Перейти к ответам

Ответы на вопрос

Внимание! Ответы на вопросы дают живые люди. Они могут содержать ошибочную информацию, заблуждения, а также ответы могут быть сгенерированы нейросетями. Будьте внимательны. Если вы уверены, что ответ неверный, нажмите кнопку "Пожаловаться" под ответом.
Отвечает Вишневецкая Кристина.
1) H2O+2Na=Na2O+H2 , реакция замещения
2) CO2+CaO= CaCO3 коэффициенты не нужны, так как вступившие вещества до реакции остались в таком же количестве после реакции. Реакция соединения.
3) KOH+HBr= KBr+H2O - Реакция обмена
4) 2Al+6HCl= 2AlCl3+3H2 - реакция замещения
5) 2KClO3=2KCl+3O2 - реакция разложения
0 0
Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Balancing Chemical Equations and Identifying Reaction Types

Balancing chemical equations involves adjusting the coefficients in front of the chemical formulas to ensure that the number of atoms of each element is the same on both sides of the equation. To balance the equations you provided, follow these steps:

1. Start by counting the number of atoms of each element on both sides of the equation. 2. Adjust the coefficients in front of the formulas to balance the number of atoms on each side. 3. Double-check that the number of atoms of each element is the same on both sides of the equation.

Let's go through each equation and balance them one by one:

Equation 1: H2O + Na → H2 + CO2

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides.

1. Count the number of atoms: - Hydrogen (H): 2 on the left, 2 on the right - Oxygen (O): 1 on the left, 2 on the right - Sodium (Na): 1 on the left, 0 on the right - Carbon (C): 0 on the left, 1 on the right

2. Balance the equation: - H2O + 2Na → H2 + Na2CO3

The balanced equation is: H2O + 2Na → H2 + Na2CO3

The type of reaction is a single displacement reaction.

Equation 2: CaO → CaCO3

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides.

1. Count the number of atoms: - Calcium (Ca): 1 on the left, 1 on the right - Oxygen (O): 1 on the left, 3 on the right - Carbon (C): 0 on the left, 1 on the right

2. Balance the equation: - CaO → CaCO3

The balanced equation is: CaO → CaCO3

The type of reaction is a decomposition reaction.

Equation 3: KOH + HBr → H2O + KBr

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides.

1. Count the number of atoms: - Hydrogen (H): 1 on the left, 2 on the right - Oxygen (O): 1 on the left, 1 on the right - Potassium (K): 1 on the left, 1 on the right - Bromine (Br): 1 on the left, 1 on the right

2. Balance the equation: - KOH + HBr → H2O + KBr

The balanced equation is: KOH + HBr → H2O + KBr

The type of reaction is a double displacement reaction.

Equation 4: Al + 3HCl → AlCl3 + 3H2

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides.

1. Count the number of atoms: - Hydrogen (H): 1 on the left, 6 on the right - Chlorine (Cl): 1 on the left, 3 on the right - Aluminum (Al): 1 on the left, 1 on the right

2. Balance the equation: - 2Al + 6HCl → 2AlCl3 + 3H2

The balanced equation is: 2Al + 6HCl → 2AlCl3 + 3H2

The type of reaction is a single displacement reaction.

Equation 5: KClO3 → KCl + 3O2

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides.

1. Count the number of atoms: - Potassium (K): 1 on the left, 1 on the right - Chlorine (Cl): 1 on the left, 1 on the right - Oxygen (O): 3 on the left, 2 on the right

2. Balance the equation: - 2KClO3 → 2KCl + 3O2

The balanced equation is: 2KClO3 → 2KCl + 3O2

The type of reaction is a decomposition reaction.

I hope this helps! Let me know if you have any further questions.

0 0

Топ вопросов за вчера в категории Химия

Последние заданные вопросы в категории Химия

Задать вопрос