Question

Какое количество вещества оксида кальция может прореагировать с соляной кислотой (HCl) массой 7,3 г. Какая масса пи этом получится? с дано пожалуйста,спасибо заранее!

Answer 1

CaO+2HCl=H2O+CaCL2
Дано:
m HCl=7.3 г
Hайти:
n CaO-?
m CaCl2-?
CaO+2HCl=H2O+CaCL2
n HCl=7.3/36.5=0.2 моль
n CaO=0.2/2=0.1 моль по уравнению реакции
n CaCl2=0.1 моль
m CaCL2=0.1*111=11.1 г

Answer 2

Stoichiometry Calculation for the Reaction between Calcium Oxide and Hydrochloric Acid

To calculate the amount of calcium oxide (CaO) that can react with hydrochloric acid (HCl) and the resulting mass of the product, we can use stoichiometry.

Given: - Mass of hydrochloric acid (HCl) = 7.3 g

Step 1: Balanced Chemical Equation

The balanced chemical equation for the reaction between calcium oxide and hydrochloric acid is: ``` CaO + 2HCl -> CaCl2 + H2O ``` This equation shows that 1 mole of CaO reacts with 2 moles of HCl to produce 1 mole of CaCl2 and 1 mole of H2O.

Step 2: Calculate Moles of HCl

To find the moles of HCl, we use the formula: ``` moles = mass / molar mass ``` The molar mass of HCl is approximately 36.46 g/mol.

Calculation: ``` moles of HCl = 7.3 g / 36.46 g/mol moles of HCl ≈ 0.2 moles ```

Step 3: Determine Moles of CaO

Using the balanced chemical equation, we can see that 1 mole of CaO reacts with 2 moles of HCl. Therefore, the moles of CaO can be calculated as: ``` moles of CaO = 0.2 moles / 2 moles of CaO = 0.1 moles ```

Step 4: Calculate Mass of CaO

To find the mass of CaO that can react with the given amount of HCl, we use the formula: ``` mass = moles * molar mass ``` The molar mass of CaO is approximately 56.08 g/mol.

Calculation: ``` mass of CaO = 0.1 moles * 56.08 g/mol mass of CaO = 5.608 g ```

Result: The amount of calcium oxide (CaO) that can react with 7.3 g of hydrochloric acid (HCl) is approximately 5.608 g.