Question

какая m(H2) получится если в реакцию с HNO3 вступает 3,5 моль (AI) спасибо!

Answer 1

Какой бы концентрации ни была азотная кислота при взаимодействии с металлами никогда не получится водород. В задаче ошибка

Answer 2

Reaction and Calculation

To find the mass of water (H2O) produced when 3.5 moles of aluminum (Al) react with HNO3, we can use the balanced chemical equation for the reaction and perform the necessary calculations.

The balanced chemical equation for the reaction between aluminum and nitric acid (HNO3) is: 2Al + 6HNO3 → 2Al(NO3)3 + 3H2

From the balanced equation, we can see that 2 moles of aluminum react with 6 moles of nitric acid to produce 3 moles of hydrogen gas and aluminum nitrate.

Given that 3.5 moles of aluminum (Al) are reacting, we can calculate the moles of water (H2O) produced using the stoichiometry of the reaction.

Calculation

Using the stoichiometry of the reaction, we can calculate the moles of water (H2O) produced: - Moles of Al = 3.5 - Moles of H2O produced = (3.5 moles Al) * (3 moles H2O / 2 moles Al)

Result

The moles of water (H2O) produced when 3.5 moles of aluminum (Al) react with HNO3 is 5.25 moles.

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