Question

В результате разложения 360 г чистой воды под действием электрического тока получено 300 г.кислорода .Каков процент выхода полученного кислорода?

Answer 1

Решение во вложении.Если под электр.разложение аналогичное,то всё верно.

Answer 2

Calculation of Oxygen Yield

To calculate the percentage yield of oxygen obtained from the electrolysis of 360 g of pure water, we need to compare the amount of oxygen obtained (300 g) to the theoretical maximum yield.

The chemical equation for the electrolysis of water is:

2H2O(l) -> 2H2(g) + O2(g)

From this equation, we can see that for every 2 moles of water, we should obtain 1 mole of oxygen gas. The molar mass of water (H2O) is approximately 18 g/mol, and the molar mass of oxygen (O2) is approximately 32 g/mol.

To calculate the theoretical maximum yield of oxygen, we can use the following equation:

(300 g O2) / (32 g/mol O2) = 9.375 mol O2

Since 1 mole of oxygen is obtained from 2 moles of water, we can calculate the theoretical maximum yield of oxygen in moles:

9.375 mol O2 * (2 mol H2O / 1 mol O2) = 18.75 mol H2O

Now, we can calculate the percentage yield of oxygen:

(18.75 mol H2O / 360 g H2O) * 100% = 5.21%

Therefore, the percentage yield of oxygen obtained from the electrolysis of 360 g of pure water is approximately 5.21%.