Question

при сжигании 2 5 моль этилена выделилась теплота 3500 кДЖ. Составьте термохимическое уравнение этой реакции

Answer 1

2,5 моль                                                    3 500 кДж 

$C_2H_4+3O_2=2CO_2+2H_2O+Q$

1 моль                                                         х кДж

при сжигании 2,5 моль этилена виделяется 3 500 кДж энергии, а

при 1 моль____________________________х кДж, откуда

х=1*3500/2,5=1400 кДж ,значит термохимическое уравнение таково:$C_2H_2+3O_2=2CO_2+2H_2O; \delta{H}=-1400$кДж

 

 

 

 

 

 

 

 

Answer 2

C2H4+3O2=2CO2+2H2O+ 3500кдж

Answer 3

Thermochemical Equation for the Combustion of 2.5 Moles of Ethylene

When 2.5 moles of ethylene are burned, 3500 kJ of heat is released. The thermochemical equation for this reaction can be represented as follows:

C2H4(g) + 3 O2(g) → 2 CO2(g) + 2 H2O(l) ΔH = -3500 kJ.

In this balanced equation, 2.5 moles of ethylene (C2H4) react with 7.5 moles of oxygen (O2) to produce 5 moles of carbon dioxide (CO2) and 5 moles of water (H2O), with the release of 3500 kJ of heat.

This equation represents the combustion of ethylene, where ethylene reacts with oxygen to produce carbon dioxide and water, releasing a significant amount of heat in the process.

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