Question

Укажите среди реакций окислительно-восстановительные, определите окислители и восстановители.1) S + Hg = HgS2) HgS + O2 = Hg + SO23) SO2 + 2NaOH = Na2SO3 + H2O4) Na2 SO3 = NaO + SO25) 2SO2 + O2 = 2SO3 6) SO3 + H2O = H2SO4

Answer 1

1) S(окисл) + Hg(восст) = HgS
2) HgS(восст) + O2(окисл) = Hg + SO2
3) 2SO2(восст) + O2(окисл) = 2SO3 

Answer 2

Reactions and Identification of Oxidizing and Reducing Agents

Let's analyze the given reactions and identify the oxidizing and reducing agents involved.

1) S + Hg = HgS - In this reaction, sulfur (S) is being oxidized to form mercury(II) sulfide (HgS). - The reducing agent is sulfur (S), as it loses electrons and gets oxidized. - The oxidizing agent is mercury (Hg), as it gains electrons and gets reduced. [[1]]

2) HgS + O2 = Hg + SO2 - In this reaction, mercury(II) sulfide (HgS) is being oxidized to form mercury (Hg) and sulfur dioxide (SO2). - The reducing agent is mercury(II) sulfide (HgS), as it loses electrons and gets oxidized. - The oxidizing agent is oxygen (O2), as it gains electrons and gets reduced. [[2]]

3) SO2 + 2NaOH = Na2SO3 + H2O - In this reaction, sulfur dioxide (SO2) is being reduced to form sodium sulfite (Na2SO3) and water (H2O). - The oxidizing agent is sodium hydroxide (NaOH), as it loses electrons and gets oxidized. - The reducing agent is sulfur dioxide (SO2), as it gains electrons and gets reduced. [[3]]

4) Na2SO3 = NaO + SO2 - In this reaction, sodium sulfite (Na2SO3) is being oxidized to form sodium oxide (NaO) and sulfur dioxide (SO2). - The reducing agent is sodium sulfite (Na2SO3), as it loses electrons and gets oxidized. - The oxidizing agent is not explicitly mentioned in the given reaction.

5) 2SO2 + O2 = 2SO3 - In this reaction, sulfur dioxide (SO2) is being oxidized to form sulfur trioxide (SO3). - The reducing agent is sulfur dioxide (SO2), as it loses electrons and gets oxidized. - The oxidizing agent is oxygen (O2), as it gains electrons and gets reduced. [[4]]

6) SO3 + H2O = H2SO4 - In this reaction, sulfur trioxide (SO3) is being hydrated to form sulfuric acid (H2SO4). - The reducing agent is not explicitly mentioned in the given reaction. - The oxidizing agent is sulfur trioxide (SO3), as it gains electrons and gets reduced.

To summarize: - In reaction 1, sulfur (S) is the reducing agent, and mercury (Hg) is the oxidizing agent. - In reaction 2, mercury(II) sulfide (HgS) is the reducing agent, and oxygen (O2) is the oxidizing agent. - In reaction 3, sulfur dioxide (SO2) is the reducing agent, and sodium hydroxide (NaOH) is the oxidizing agent. - In reaction 4, sodium sulfite (Na2SO3) is the reducing agent, and the oxidizing agent is not explicitly mentioned. - In reaction 5, sulfur dioxide (SO2) is the reducing agent, and oxygen (O2) is the oxidizing agent. - In reaction 6, sulfur trioxide (SO3) is the reducing agent, and the oxidizing agent is not explicitly mentioned.