Question

Рассчитайте сколько граммов серной кислоты можно получить при взаимодействии 8г SO3 с водой SO3+H2O=H2So4

Answer 1

8г                   хг
SO3+H2O=H2SO3
80г                   98г

х= 8*98/80=9,8г m (H2SO4)

Answer 2

V(SO3) = 8 : 80 = 0,1 моль
v(H2SO4) = v(SO3) = 0,1 моль
m(H2SO4) = 0,1 * 98 = 9,8 г

Answer 3

Calculating the Amount of Sulfuric Acid Produced

To calculate the amount of sulfuric acid (H2SO4) produced when 8g of sulfur trioxide (SO3) reacts with water (H2O), we can use the balanced chemical equation for the reaction:

SO3 + H2O → H2SO4

The molar mass of SO3 is 80.06 g/mol, and the molar mass of H2SO4 is 98.08 g/mol.

First, we need to calculate the number of moles of SO3: ``` moles of SO3 = mass of SO3 / molar mass of SO3 moles of SO3 = 8g / 80.06 g/mol moles of SO3 ≈ 0.1 mol ```

According to the balanced chemical equation, 1 mole of SO3 produces 1 mole of H2SO4. Therefore, the number of moles of H2SO4 produced is also approximately 0.1 mol.

Finally, we can calculate the mass of H2SO4 produced: ``` mass of H2SO4 = moles of H2SO4 × molar mass of H2SO4 mass of H2SO4 = 0.1 mol × 98.08 g/mol mass of H2SO4 ≈ 9.81 g ```

Result

When 8g of SO3 reacts with water, approximately 9.81 grams of sulfuric acid can be produced.

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