Question

Бензол масса 7,8 грамм вступает в реакцию с водородом 3,36 л,получает C6H12 Найти массу C6H12

Answer 1

С6Н6+3Н2=С6Н12
n(C6H6)=7.8/78=0.1 моль
n(H2)=3.36/22.4=0.15 моль,
так как по уравнению реакции надо 3 моль Н2, то 1 моль сотавляет 0,15/3=0,05 моль, следовательно n(H2) в недостатке, поэтому ведем расчёт по нему, составляем пропорцию
0,15/3=х/1, где х n(C6H12),
x=n(C6H12)=0.15/3*1=0.05
M(C6H12)=84,
m(C6H12)=84*0.05=4.2 грамм
ответ 4,2 грамм

Answer 2

Calculating the Mass of C6H12

To find the mass of C6H12 produced when 7.8 grams of benzene (C6H6) reacts with 3.36 liters of hydrogen gas (H2), we can use the balanced chemical equation for the reaction between benzene and hydrogen to produce cyclohexane (C6H12).

The balanced chemical equation for the reaction is: C6H6 + 3H2 → C6H12

From the balanced chemical equation, we can see that 1 mole of benzene reacts with 3 moles of hydrogen to produce 1 mole of cyclohexane.

Steps to Calculate the Mass of C6H12

1. Convert grams of benzene to moles: - The molar mass of benzene (C6H6) is approximately 78.11 g/mol. - Using the formula: moles = mass / molar mass, we can calculate the moles of benzene.

2. Convert liters of hydrogen to moles: - The molar volume of a gas at standard temperature and pressure (STP) is 22.4 liters per mole. - Using the formula: moles = volume (in liters) / molar volume, we can calculate the moles of hydrogen.

3. Determine the limiting reactant: - Compare the moles of benzene and hydrogen to identify the limiting reactant.

4. Calculate moles of C6H12 produced: - Since the reaction is 1:3 for benzene to hydrogen, the moles of C6H12 produced will be equal to the moles of benzene (if it is the limiting reactant).

5. Convert moles of C6H12 to grams: - Using the molar mass of cyclohexane (C6H12), we can convert moles to grams.

Calculation

1. Moles of Benzene (C6H6): - Moles = 7.8 g / 78.11 g/mol - Moles ≈ 0.1 mol

2. Moles of Hydrogen (H2): - Moles = 3.36 L / 22.4 L/mol - Moles ≈ 0.15 mol

3. Limiting Reactant: - Since benzene and hydrogen are in a 1:3 ratio, benzene is the limiting reactant.

4. Moles of C6H12 Produced: - Moles of C6H12 = Moles of Benzene - Moles of C6H12 ≈ 0.1 mol

5. Mass of C6H12 Produced: - Mass = Moles × Molar Mass - Mass = 0.1 mol × (6 × 12.01 g/mol + 12 × 1.01 g/mol) - Mass ≈ 84.18 g

The mass of C6H12 produced is approximately 84.18 grams.