Question

Найти колличество воды полученного при взаимодействии 20 грм водорода с кислородом.

Answer 1

2H2+O2=2H2O

n(H2)=20/2=10 моль

m( H2O)=10*18=180 г

Answer 2

Calculating the Amount of Water Produced from the Reaction of Hydrogen with Oxygen

To calculate the amount of water produced from the reaction of 20 grams of hydrogen with oxygen, we can use the balanced chemical equation for the reaction.

The balanced chemical equation for the reaction of hydrogen with oxygen to produce water is: 2H2 + O2 → 2H2O

According to the stoichiometry of the balanced chemical equation, 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water.

Calculation

Given: - Mass of hydrogen (H2) = 20 grams

1. Convert the mass of hydrogen to moles using the molar mass of hydrogen: - Molar mass of hydrogen (H2) = 2.016 g/mol - Moles of hydrogen = Mass of hydrogen / Molar mass of hydrogen - Moles of hydrogen = 20 g / 2.016 g/mol

2. Determine the moles of water produced using the mole ratio from the balanced chemical equation: - Moles of water = Moles of hydrogen * (2 moles of water / 2 moles of hydrogen)

3. Convert the moles of water to grams using the molar mass of water: - Molar mass of water (H2O) = 18.015 g/mol - Mass of water produced = Moles of water * Molar mass of water

Result

The amount of water produced from the reaction of 20 grams of hydrogen with oxygen is 40.14 grams.