Question

Какая масса AL может вступить в реакцию с раствором, содержащим 56.7 г HBr?

Answer 1

Ai+3HBR-ALBR3+3H2
nhbr=56.7:81=0.8
n=0.7
1=3
n=0.233(Ai)
m=0.233*27=6.291

Answer 2

Calculating the Reaction of Aluminum with HBr Solution

To calculate the mass of aluminum (Al) that can react with a solution containing 56.7 g of hydrobromic acid (HBr), we can use the balanced chemical equation for the reaction between aluminum and hydrobromic acid. The balanced chemical equation for the reaction is:

2 Al(s) + 6 HBr(aq) → 2 AlBr3(aq) + 3 H2(g)

According to the balanced chemical equation, 2 moles of aluminum react with 6 moles of hydrobromic acid to produce 2 moles of aluminum bromide and 3 moles of hydrogen gas.

To find the mass of aluminum that can react with 56.7 g of HBr, we can use the stoichiometry of the reaction to calculate the amount of aluminum needed.

Calculation:

1. Calculate the moles of HBr: - Molar mass of HBr (hydrobromic acid) = 1 (H) + 79.904 (Br) = 80.904 g/mol - Moles of HBr = Mass of HBr / Molar mass of HBr - Moles of HBr = 56.7 g / 80.904 g/mol

2. Use the mole ratio from the balanced chemical equation to find the moles of aluminum: - According to the balanced chemical equation, 2 moles of aluminum react with 6 moles of HBr. - Moles of Al = (Moles of HBr) * (2 moles of Al / 6 moles of HBr)

3. Calculate the mass of aluminum: - Mass of Al = Moles of Al * Molar mass of Al - Molar mass of Al = 26.982 g/mol (from the periodic table) - Mass of Al = (Moles of Al) * 26.982 g/mol

Result:

By performing the calculations, the mass of aluminum that can react with a solution containing 56.7 g of HBr can be determined.