Question

1)сколько молекул содержится в 67,2 л оксида углерода (II)? 2) Какова масса сульфата бария, взятого в количестве 2 моль? 3) Определить массовые доли W (%) меди, водорода и кислорода в гидроксиде меди (II)?

Answer 1

1.18.06*10^23

2.466 грамм

3.W(Cu)=65.3%

   W(O)=32.65%

   W(H)=2%

Если надо будет решение - пиши в лс!

Answer 2

Answer:

1) Number of molecules in 67.2 L of carbon oxide (II): - The number of molecules in a gas can be calculated using Avogadro's law, which states that one mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters. - To find the number of molecules in 67.2 L of carbon oxide (II), we can use the following formula: \[ \text{Number of molecules} = \frac{\text{Volume of gas (in liters)}}{22.4} \times 6.022 \times 10^{23} \] - Substituting the given volume, we get: \[ \text{Number of molecules} = \frac{67.2}{22.4} \times 6.022 \times 10^{23} \] \[ \text{Number of molecules} = 3 \times 6.022 \times 10^{23} \] \[ \text{Number of molecules} = 1.8066 \times 10^{24} \]

Source: 2) Mass of barium sulfate for 2 moles: - The molar mass of barium sulfate (BaSO4) is 233.4 g/mol. - To find the mass of 2 moles of barium sulfate, we can use the following formula: \[ \text{Mass} = \text{Molar mass} \times \text{Number of moles} \] \[ \text{Mass} = 233.4 \times 2 \] \[ \text{Mass} = 466.8 \, \text{grams} \]

Source: 3) Mass fractions of W (%), Cu, H, and O in copper hydroxide (II): - The mass fractions of W (%), Cu, H, and O in copper hydroxide (II) can be calculated using the molar masses of the elements and the chemical formula of copper hydroxide (II), which is Cu(OH)2. - The molar masses are: - W (tungsten): 183.84 g/mol - Cu (copper): 63.55 g/mol - H (hydrogen): 1.008 g/mol - O (oxygen): 16.00 g/mol - The molar mass of Cu(OH)2 can be calculated as: \[ \text