Question

Помогите пожалуйста!!!! рассчитайте массу кислорода который может быть получен из перманганата калия массой 7,9г

Answer 1

0.05                                        x(0.025)
2KMnO4=K2MnO4 + MnO2 + O2
2                                             1
n(KMnO4)= 7.9/158=0.05
0.05/2=x/1(пропорция)
x=0.05/2=0.025(x)
m(O2)= 0.025x32=0.8г

Answer 2

Calculating the Mass of Oxygen from Potassium Permanganate

To calculate the mass of oxygen that can be obtained from potassium permanganate with a mass of 7.9g, we can use the chemical formula of potassium permanganate (KMnO4) to determine the amount of oxygen it contains.

The molar mass of potassium permanganate (KMnO4) is 158.034 g/mol From this, we can calculate the mass of oxygen in potassium permanganate.

The chemical formula of potassium permanganate is KMnO4. From this formula, we can see that there are 4 oxygen atoms in 1 molecule of potassium permanganate.

Using the molar mass of oxygen (O), which is approximately 16.00 g/mol we can calculate the mass of oxygen in potassium permanganate.

Calculation:

1. Calculate the molar mass of oxygen in potassium permanganate: - Molar mass of potassium permanganate (KMnO4) = 158.034 g/mol - Molar mass of oxygen (O) = 16.00 g/mol - Number of oxygen atoms in potassium permanganate = 4

Mass of oxygen in potassium permanganate = (Molar mass of oxygen) * (Number of oxygen atoms) = 16.00 g/mol * 4 = 64.00 g/mol

2. Calculate the mass of oxygen that can be obtained from 7.9g of potassium permanganate: - Mass of potassium permanganate = 7.9g

Mass of oxygen = (Mass of oxygen in potassium permanganate) * (Mass of potassium permanganate) / (Molar mass of potassium permanganate) Mass of oxygen = 64.00 g/mol * 7.9g / 158.034 g/mol Mass of oxygen ≈ 3.19g

The mass of oxygen that can be obtained from potassium permanganate with a mass of 7.9g is approximately 3.19g.