Question

Сколько времени потребуется пропускать ток силой 5 А, чтобы получить 1,5 л «гремучего газа» (20 °С; 98,64 кПа) при электролизе воды?Подскажите пожалуйста,заранее спасибо.

Answer 1

1) "Гремучий газ" - 2 V H2+1 V O2;

2) 2*х+х = 1.5, 2*х = 1 л - значит в 1.5 л смеси сод-ся 1 л H2;

3) по з. Менделеева-Клапейрона, n H2 = (98.64*1)/(8.314*(273+20)) = 0.04 моль;

4) t (сек.) = (0.04*2*96485)/(1*5) = 1543.76 сек. или 25 мин. 43.76 сек.

Answer 2

Electrolysis of Water to Produce "Gremuchiy Gaz"

To calculate the time required to pass a current of 5 A during the electrolysis of water to produce 1.5 L of "gremuchiy gaz" (at 20 °C and 98.64 kPa), we need to consider the stoichiometry of the reaction and the Faraday's law of electrolysis.

The electrolysis of water involves the decomposition of water molecules into hydrogen gas (H2) and oxygen gas (O2) through the following reaction:

2H2O(l) -> 2H2(g) + O2(g)

According to Faraday's law of electrolysis, the amount of substance produced or consumed during electrolysis is directly proportional to the quantity of electricity passed through the electrolyte. The relationship is given by the equation:

Q = nF

Where: - Q is the quantity of electricity passed (in coulombs) - n is the number of moles of substance produced or consumed - F is the Faraday constant, which is equal to 96,485 C/mol

To calculate the time required, we need to determine the number of moles of "gremuchiy gaz" produced and then use Faraday's law to find the quantity of electricity passed.

Calculation:

1. Determine the number of moles of "gremuchiy gaz" produced: - 1.5 L of "gremuchiy gaz" at 20 °C and 98.64 kPa can be converted to moles using the ideal gas law. - The molar volume of an ideal gas at standard temperature and pressure (STP) is 22.4 L/mol. - Therefore, the number of moles of "gremuchiy gaz" produced is: ``` n = (1.5 L) / (22.4 L/mol) ```

2. Calculate the quantity of electricity passed: - Using Faraday's law, we can calculate the quantity of electricity passed using the equation: ``` Q = nF ``` - Substituting the values, we get: ``` Q = (n) * (F) ```

3. Calculate the time required: - The current (I) is given as 5 A. - The time (t) required can be calculated using the equation: ``` t = Q / I ```

Answer:

To obtain 1.5 L of "gremuchiy gaz" (at 20 °C and 98.64 kPa) through the electrolysis of water with a current of 5 A, the time required can be calculated as follows:

1. Determine the number of moles of "gremuchiy gaz" produced: - The number of moles of "gremuchiy gaz" produced is approximately equal to 0.067 mol.

2. Calculate the quantity of electricity passed: - The quantity of electricity passed is approximately equal to 6,462 C.

3. Calculate the time required: - The time required to pass a current of 5 A to produce 1.5 L of "gremuchiy gaz" is approximately equal to 1,292 seconds or 21.5 minutes.

Please note that these calculations are based on the assumptions and data provided. The actual time required may vary depending on various factors.