Question

В 250 мл раствора содержится 0,53 г Na2Co3. Вычислить титр, молярную массу и нормальную концентрацию раствора

Answer 1

Молярная масса M(Na2CO3)=23*2+12+16*3=106 г/моль
количество вещества  n(Na2CO3)= 0.53 г / 106 г/моль=0.005 моль
молярная концентрация (молярность)  С(Na2CO3)=n/V=0.005 моль / 0.25 л = 0.02 л/моль
титр  Т=m/V=0.53 г / 0.25 л = 2.12 г/л
нормальная концентрация (нормальность) ?Сн=С*z=0.005 г/моль * 2 = 0.01 г/экв?

Answer 2

Calculation of Molar Mass and Normal Concentration of the Solution

To calculate the molar mass and normal concentration of the solution, we need to know the mass of the solute (Na2CO3) and the volume of the solution (250 ml).

Given: - Mass of Na2CO3 = 0.53 g - Volume of solution = 250 ml

To calculate the molar mass of Na2CO3, we need to know the atomic masses of sodium (Na), carbon (C), and oxygen (O). The atomic masses are as follows: - Na: 22.99 g/mol - C: 12.01 g/mol - O: 16.00 g/mol

The molar mass of Na2CO3 can be calculated as follows: - Molar mass of Na2CO3 = (2 * Na) + C + (3 * O)

Let's calculate the molar mass of Na2CO3: - Molar mass of Na2CO3 = (2 * 22.99) + 12.01 + (3 * 16.00) g/mol

Now, let's calculate the normal concentration of the solution. Normal concentration is defined as the number of gram equivalents of solute per liter of solution. To calculate the normal concentration, we need to know the number of gram equivalents of Na2CO3.

The number of gram equivalents can be calculated using the formula: - Gram equivalents = (Mass of solute / Molar mass of solute)

The normal concentration can be calculated using the formula: - Normal concentration = (Gram equivalents / Volume of solution in liters)

Let's calculate the normal concentration of the solution: - Gram equivalents of Na2CO3 = (Mass of Na2CO3 / Molar mass of Na2CO3) - Normal concentration = (Gram equivalents of Na2CO3 / Volume of solution in liters)

Now, let's perform the calculations.

Step 1: Calculation of Molar Mass of Na2CO3 - Molar mass of Na2CO3 = (2 * 22.99) + 12.01 + (3 * 16.00) g/mol - Molar mass of Na2CO3 = 105.99 g/mol

Step 2: Calculation of Normal Concentration of the Solution - Gram equivalents of Na2CO3 = (0.53 g / 105.99 g/mol) - Gram equivalents of Na2CO3 = 0.00499 eq

- Volume of solution in liters = 250 ml / 1000 ml/L - Volume of solution in liters = 0.25 L

- Normal concentration = (0.00499 eq / 0.25 L) - Normal concentration = 0.01996 eq/L

Answer:

The molar mass of Na2CO3 is 105.99 g/mol, and the normal concentration of the solution is 0.01996 eq/L.