Question

К 200 г раствора с массовой долей нитрата натрия 25 % дабавили 50 мил воды Вычеслите массовую долю соли в полученом растворе помогите

Answer 1

Дано: (розчину) = 200г.
          (Na )= 8%
          m( O) = 50г.
Знайти:  (NaN) - ?
Розв*язання: Спочатку знайдемо масу NaN. З формули W = , отже m( NaNO3) = 200*0.8 = 160 г. Далф найдемо масу нового розчину до якого долили воду: (рочину) = 200+50 = 250 г. Залишилось найти (NaNO3) =  = 0.64 * 100%= 64%

Answer 2

Calculation of Mass Fraction of Salt in the Solution

To calculate the mass fraction of salt in the solution, we need to consider the initial mass of the sodium nitrate and the final mass of the solution after adding water.

Given: - Initial mass of the solution = 200 g - Mass fraction of sodium nitrate = 25% - Amount of water added = 50 mL

To solve this problem, we can follow these steps:

1. Calculate the mass of sodium nitrate in the initial solution: - Mass of sodium nitrate = Mass of solution * Mass fraction of sodium nitrate - Mass of sodium nitrate = 200 g * 0.25 = 50 g

2. Calculate the final mass of the solution after adding water: - Final mass of solution = Initial mass of solution + Mass of water added - Final mass of solution = 200 g + 50 g = 250 g

3. Calculate the mass fraction of salt in the final solution: - Mass fraction of salt = Mass of sodium nitrate / Final mass of solution - Mass fraction of salt = 50 g / 250 g = 0.2

Therefore, the mass fraction of salt in the final solution is 0.2 or 20%.

Please note that the calculation assumes that the volume of the solution remains constant when water is added.