Question

При взаимодействии фосфора массой 6.2 гр. с хлоридом был получен пентахлорид фосфора(PCL5) массой 12г.Найти массовую долю выхода продукта реакции от теоритически возможного.

Answer 1

Найти:
W выхода (PCl5) - ?

Дано:
m (P) = 6,2 г
M (P) = 31 г/моль 
M (PCl5) = 208,5 г/моль
m практ. (PCl5) = 12 г 

Решение: 
2P + 5Cl2 = 2PCl5

1. n (P) = m/M = 6,2/31 = 0,2 моль

2. n (PCl5) = n (P) = 0,2 моль

3. m теор. (PCl5) = n х M = 0,2 х 208,5 г 

4. W выхода (PCl5) = m практ. / m теор. = 12 / 208,5 = 0,058 (5,8 %) 

Answer 2

  2P+5CI2=2PCI5

1.n(P)=6,2 г / 31 г/моль=0,2 моль

2. по уравнению : 

  0,2 моль / 2 моль=x моль /2 моль

значит, n(PCI5)=0,2 моль

3.m(PCI5)=0,2 моль * 208,5 г/моль=41,7 г

 !нашли масу теоретическую

4.чтобы найти массовую долю выхода продукта реакции от теоретически возможно нужно : массу практическую (дана в условии) разделить на массу теоретическую (ту,что нашли по уравнению) и умножить на 100 %

w(PCI5)=12 г /41,7 г *100 %=29 %

Answer 3

Calculation of the Mass Fraction of the Reaction Product

To calculate the mass fraction of the reaction product, we need to compare the mass of the obtained product (pentafluorophosphorus, PCl5) with the theoretical mass of the product that would be obtained if the reaction proceeded to completion.

Given: - Mass of phosphorus used in the reaction = 6.2 g - Mass of pentafluorophosphorus (PCl5) obtained = 12 g

To find the mass fraction of the reaction product, we can use the following formula:

Mass Fraction = (Mass of Product Obtained / Theoretical Mass of Product) x 100

The theoretical mass of the product can be calculated using the molar masses of the reactants and products involved in the reaction. However, since the molar masses are not provided in the question, we will not be able to calculate the exact theoretical mass.

Instead, we can calculate the mass fraction based on the assumption that the reaction proceeds to completion, which means all the phosphorus reacts to form PCl5.

Let's calculate the mass fraction using this assumption:

Mass Fraction = (12 g / 6.2 g) x 100

Calculating the above expression gives us the mass fraction of the reaction product.

Please note that without the molar masses of the reactants and products, we cannot determine the exact theoretical mass or the actual yield of the reaction. The calculation above assumes complete conversion of phosphorus to pentafluorophosphorus (PCl5) for simplicity.