Question

Амфотерные гидроксиды в реакции с кислотами ведут себя как.....

Answer 1

ведут себя,как основания

Answer 2

Амфотерные гидроксиды в реакции с кислотами ведут себя как основания.

Zn(OH)2 + 2HCl = ZnCl2 + 2H2O

Так же, как и:

Ca(OH)2 + 2HCl = CaCl2 + H2O

Zn(OH)2 - амфотерный гидроксид, Са(ОН)2 - основной

Answer 3

Amphoteric Hydroxides in Reaction with Acids

Amphoteric hydroxides are substances that can act as both bases and acids, depending on the reaction conditions. They can react with both strong acids and strong bases. When amphoteric hydroxides react with acids, they behave as bases and undergo neutralization reactions.

Here are some examples of amphoteric hydroxides and their reactions with acids:

1. Aluminum Hydroxide (Al(OH)3): Aluminum hydroxide can react with acids to form salts and water. For example, when aluminum hydroxide reacts with hydrochloric acid (HCl), it forms aluminum chloride (AlCl3) and water (H2O).

Equation: Al(OH)3 + 3HCl → AlCl3 + 3H2O

2. Zinc Hydroxide (Zn(OH)2): Zinc hydroxide can also react with acids to form salts and water. When zinc hydroxide reacts with sulfuric acid (H2SO4), it forms zinc sulfate (ZnSO4) and water.

Equation: Zn(OH)2 + H2SO4 → ZnSO4 + 2H2O

3. Copper Hydroxide (Cu(OH)2): Copper hydroxide can react with nitric acid (HNO3) to form copper nitrate (Cu(NO3)2) and water.

Equation: Cu(OH)2 + 2HNO3 → Cu(NO3)2 + 2H2O

4. Iron(III) Hydroxide (Fe(OH)3): Iron(III) hydroxide can react with nitric acid (HNO3) to form iron(III) nitrate (Fe(NO3)3) and water.

Equation: Fe(OH)3 + 3HNO3 → Fe(NO3)3 + 3H2O

5. Magnesium Hydroxide (Mg(OH)2): Magnesium hydroxide can react with hydrochloric acid (HCl) to form magnesium chloride (MgCl2) and water.

Equation: Mg(OH)2 + 2HCl → MgCl2 + 2H2O

These are just a few examples of amphoteric hydroxides and their reactions with acids. Other amphoteric hydroxides, such as those of sodium (Na), lead (Pb), and chromium (Cr), also exhibit similar behavior when reacting with acids.

It's important to note that the specific reaction products may vary depending on the stoichiometry and conditions of the reaction.

I hope this explanation helps! Let me know if you have any further questions.