Question

Помогите пожалуйста с задачей! ООчень буду благодарна, сколько молей и граммов оксида кальция полностью прореагируют с 1,12 дм^3 газообразного хлорида водорода (при нормальных условиях)?

Answer 1

Ca + 2HCl = CaCl2 + H2↑
n(HCl) = 1,12/22,4 = 0,05 моль
n(Ca) = 0,5*0,05 = 0,025 моль
m(Ca) = 0,025*40 = 1 г

Answer 2

Calculation of the Number of Moles and Grams of Calcium Oxide

To determine the number of moles and grams of calcium oxide that will completely react with 1.12 dm^3 of gaseous hydrogen chloride at normal conditions, we need to use the balanced chemical equation for the reaction between calcium oxide (CaO) and hydrogen chloride (HCl).

The balanced chemical equation for the reaction is as follows:

CaO + 2HCl → CaCl2 + H2O

From the balanced equation, we can see that 1 mole of calcium oxide reacts with 2 moles of hydrogen chloride.

To calculate the number of moles of calcium oxide, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas (at normal conditions, it is approximately 1 atm) - V is the volume of the gas (1.12 dm^3) - n is the number of moles of the gas (what we want to find) - R is the ideal gas constant (0.0821 L·atm/(mol·K)) - T is the temperature of the gas (at normal conditions, it is approximately 273 K)

Plugging in the values, we can solve for n:

n = PV / RT

Substituting the values, we get:

n = (1 atm) * (1.12 dm^3) / (0.0821 L·atm/(mol·K) * 273 K)

Simplifying the equation, we find:

n ≈ 0.051 moles of hydrogen chloride

Since 1 mole of calcium oxide reacts with 2 moles of hydrogen chloride, we can conclude that the number of moles of calcium oxide required for the reaction is twice the number of moles of hydrogen chloride:

n(CaO) = 2 * n(HCl) ≈ 2 * 0.051 moles ≈ 0.102 moles of calcium oxide.

To calculate the mass of calcium oxide, we need to use the molar mass of calcium oxide, which is approximately 56.08 g/mol.

Mass(CaO) = n(CaO) * molar mass(CaO) ≈ 0.102 moles * 56.08 g/mol ≈ 5.72 grams of calcium oxide.

Therefore, approximately 0.102 moles or 5.72 grams of calcium oxide will completely react with 1.12 dm^3 of gaseous hydrogen chloride at normal conditions.

Please note that the values provided are approximate and may vary slightly depending on the actual conditions and the molar mass used for calcium oxide.