Question

Рассчитайте массовые доли каждого из элементов в нитрате кальция

Answer 1

M(Ca(NO3)2)=40+(23+16*3)2=182 г
ω(Ca)=40/182*100=22%
ω(N)=23/182*100=13%
ω(O3)=48/182*100=26%

Answer 2

Calculation of Mass Fractions in Calcium Nitrate

To calculate the mass fractions of each element in calcium nitrate (Ca(NO3)2), we need to determine the molar mass of each element and the compound as a whole.

The molar mass of an element is the mass of one mole of that element, expressed in grams per mole (g/mol). The molar mass of a compound is the sum of the molar masses of its constituent elements.

Let's calculate the molar mass of each element in calcium nitrate:

- Calcium (Ca): - Atomic mass of calcium (Ca) = 40.08 g/mol - Calcium appears once in the formula, so its contribution to the molar mass is 40.08 g/mol.

- Nitrogen (N): - Atomic mass of nitrogen (N) = 14.01 g/mol - Nitrogen appears twice in the formula, so its contribution to the molar mass is 2 * 14.01 g/mol = 28.02 g/mol.

- Oxygen (O): - Atomic mass of oxygen (O) = 16.00 g/mol - Oxygen appears six times in the formula, so its contribution to the molar mass is 6 * 16.00 g/mol = 96.00 g/mol.

Now, let's calculate the molar mass of calcium nitrate:

- Molar mass of calcium nitrate (Ca(NO3)2) = (40.08 g/mol) + (28.02 g/mol) + (96.00 g/mol) = 164.10 g/mol.

To calculate the mass fraction of each element, we divide the molar mass of each element by the molar mass of the compound and multiply by 100%.

- Mass fraction of calcium (Ca) = (40.08 g/mol / 164.10 g/mol) * 100% = 24.42%.

- Mass fraction of nitrogen (N) = (28.02 g/mol / 164.10 g/mol) * 100% = 17.06%.

- Mass fraction of oxygen (O) = (96.00 g/mol / 164.10 g/mol) * 100% = 58.52%.

Therefore, the mass fractions of each element in calcium nitrate are approximately:

- Calcium (Ca): 24.42% - Nitrogen (N): 17.06% - Oxygen (O): 58.52%

Please note that these values are approximate and may vary slightly depending on the specific isotopic composition of the elements.

I hope this helps! Let me know if you have any further questions.