Question

1.Полярность ковалентной связи уменьшается в ряду: а) SO2, SeO2, TeO2 б) SeO2, SO2, TeO2 в) TeO2, SeO2, SO2 г) SeO2, TeO2, SO2 2. Степень окисления атома серы увеличивается в ряду: a)H2SO4,SO2,H2S б)S, Na2SO3,Fe2(SO4)3 в)SO3, FeS, S г)K2SO4,KHSO4,FeS

Answer 1

1. В)      Чем больше разница в ЭО элементов в веществе, тем сильнее будет полярность.

2. Б) 0 +4 +6

Answer 2

Polarities of Covalent Bonds

The polarity of a covalent bond is determined by the difference in electronegativity between the two atoms involved in the bond. Electronegativity is a measure of an atom's ability to attract electrons towards itself in a chemical bond. When the electronegativity difference is large, the bond is considered polar, while a small difference results in a nonpolar bond.

To determine the order of decreasing polarity in the given series (SO2, SeO2, TeO2), we need to compare the electronegativities of the atoms involved. According to the periodic table, oxygen (O) is more electronegative than sulfur (S), selenium (Se), and tellurium (Te).

Based on this information, we can conclude that the order of decreasing polarity in the given series is: a) SO2, SeO2, TeO2 [[1]].

Oxidation States of Sulfur

The oxidation state, also known as the oxidation number, of an atom in a compound indicates the number of electrons that the atom has gained or lost. To determine the order of increasing oxidation states of sulfur in the given series (H2SO4, SO2, H2S), we need to consider the known oxidation states of the other elements in the compounds.

In sulfuric acid (H2SO4), sulfur has an oxidation state of +6. In sulfur dioxide (SO2), sulfur has an oxidation state of +4. In hydrogen sulfide (H2S), sulfur has an oxidation state of -2.

Based on this information, we can conclude that the order of increasing oxidation states of sulfur in the given series is: a) H2SO4, SO2, H2S [[2]].

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