Question

К раствору хлорида железа (ll) с массовой долей 5% добавили избыток гидроксида натрия . в результате риакции оброзовался осадок массой 4.5 г . опредилите массу исходного раствора соли

Answer 1

Ловите решение)
Всё же просто до безобразия...

Answer 2

Calculation of the Mass of the Initial Iron(II) Chloride Solution

To determine the mass of the initial iron(II) chloride solution, we need to consider the reaction that occurred when an excess of sodium hydroxide was added to the solution. The reaction can be represented as follows:

FeCl2 + 2NaOH → Fe(OH)2 + 2NaCl

Given that a precipitate with a mass of 4.5 g was formed, we can use stoichiometry to calculate the mass of the initial iron(II) chloride solution.

From the balanced equation, we can see that the molar ratio between FeCl2 and Fe(OH)2 is 1:1. This means that the mass of the precipitate (Fe(OH)2) is equal to the mass of the iron(II) chloride (FeCl2) that reacted.

Therefore, the mass of the initial iron(II) chloride solution is 4.5 g.

Please let me know if there's anything else I can help you with!