Question

Электрон , пролетая в электрическом поле из точки А в точку В , увеличил скорость с =1000 км/с до = 3000 км/с . Найти qА - QB , если =1,76 Кл/кг .

Answer 1

мда... нельзя написать было, что нужно найти разность потенциалов...

2qU=m(v^2)-m(v0^2)

U=m((v^2)-(v0^2))/2q далее подставляешь

U=22,7 В

Answer 2

Calculation of qA - qB

To find the value of qA - qB, we need to use the equation qA - qB = m(vB - vA), where qA and qB are the charges at points A and B respectively, m is the mass of the electron, and vA and vB are the velocities at points A and B respectively.

Given: - Initial velocity, vA = 1000 km/s - Final velocity, vB = 3000 km/s - Charge-to-mass ratio, q/m = 1.76 C/kg

To calculate qA - qB, we need to determine the change in velocity (vB - vA). Let's calculate it:

vB - vA = 3000 km/s - 1000 km/s = 2000 km/s

Now, we can substitute the values into the equation:

qA - qB = (q/m) * (vB - vA) = 1.76 C/kg * 2000 km/s

To convert km/s to m/s, we need to multiply by 1000:

qA - qB = 1.76 C/kg * 2000 km/s * 1000 m/km = 1.76 C/kg * 2,000,000 m/s

Calculating the result:

qA - qB = 3,520,000 C/kg

Therefore, qA - qB is equal to 3,520,000 C/kg.

Please note that the calculation assumes the charge-to-mass ratio remains constant throughout the motion of the electron in the electric field.