Question

Сколько молекул находится внутри резинового шара обьемом 5,6 л.(н.у.) заполненного водородом? Изменится ли ответ,если в условии задачи водород заменить на: а) азот б) неизвестный газ в) водопроводную воду? Ребят, желательно на бумаге решите и пришлите задание фоткой. Когда так всё в строчку написано, ничего не понятно. И формулы, пожалуйста, напишите!

Answer 1

V= 5.6 (л)

n=V/Vm, где Vm - объем газа при н.у. = 22.4 (л/моль)
n=5.6/22.4 = 0.25 (моль)
N=Na*n, где Na - число Авогадро = 6.02*10^23 (молекул/моль)
N=6.02*10^23*0.25=1.505*10^23 (молекул)

Ответ не изменится, при замене на другие газы.

Answer 2

Calculation of the Number of Molecules in a Rubber Ball Filled with Hydrogen

To calculate the number of molecules inside a rubber ball filled with hydrogen, we need to use the ideal gas law equation. The ideal gas law equation is given by:

PV = nRT

Where: - P is the pressure of the gas (in this case, hydrogen) - V is the volume of the gas (in this case, the volume of the rubber ball) - n is the number of moles of the gas - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas (in Kelvin)

In this case, we are given the volume of the rubber ball as 5.6 L (at standard temperature and pressure, or STP). We need to convert this volume to cubic meters (m^3) to match the units of the ideal gas constant.

1 L = 0.001 m^3

Therefore, the volume of the rubber ball is 5.6 L * 0.001 m^3/L = 0.0056 m^3.

At STP, the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (K).

Now, we can rearrange the ideal gas law equation to solve for the number of moles (n):

n = PV / RT

Substituting the values into the equation:

n = (1 atm) * (0.0056 m^3) / [(8.314 J/(mol·K)) * (273.15 K)]

Calculating this expression gives us the number of moles of hydrogen gas in the rubber ball.

Calculation for Hydrogen Gas:

n = (1 atm) * (0.0056 m^3) / [(8.314 J/(mol·K)) * (273.15 K)]

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Therefore, the number of molecules of hydrogen gas in the rubber ball is:

Number of molecules = n * Avogadro's number

Calculation for Nitrogen Gas:

If we replace hydrogen with nitrogen gas, we need to recalculate the number of molecules using the same process. However, we need to consider the molar mass of nitrogen, which is approximately 28.0134 g/mol.

Using the molar mass of nitrogen, we can calculate the number of moles (n) of nitrogen gas in the rubber ball using the ideal gas law equation:

n = (1 atm) * (0.0056 m^3) / [(8.314 J/(mol·K)) * (273.15 K)]

Then, we can calculate the number of molecules of nitrogen gas in the rubber ball:

Number of molecules = n * Avogadro's number

Calculation for an Unknown Gas:

If we replace hydrogen with an unknown gas, we need more information to calculate the number of molecules accurately. We would need the molar mass of the unknown gas to calculate the number of moles (n) using the ideal gas law equation:

n = (1 atm) * (0.0056 m^3) / [(8.314 J/(mol·K)) * (273.15 K)]

Then, we can calculate the number of molecules of the unknown gas in the rubber ball:

Number of molecules = n * Avogadro's number

Calculation for Tap Water:

If we replace hydrogen with tap water, we need to consider that tap water is not a gas. It is a liquid composed of water molecules. Therefore, we cannot use the ideal gas law equation to calculate the number of molecules in this case.

Please note that the calculations provided above are based on the given information and assumptions. If you have any additional information or specific conditions, please let me know, and I will be happy to assist you further.