Question

Расположите следующие молекулы по увеличению длины связи и энергии связи: a) HCL, HF, HBr, HI b) BCl3. BeCl2, CCl4.

Answer 1

Длина связи  HF, HCl, HBr, HI, энергия - в обратном порядке (точно)


Длина связи  увелич. CCl4.  BCl3  BeCl2, энергия в обратном порядке (думаю, что так)

Answer 2

a) HCl, HF, HBr, HI

The molecules HCl, HF, HBr, and HI can be arranged in order of increasing bond length and bond energy as follows:

1. HCl: Hydrogen chloride (HCl) has the shortest bond length and highest bond energy among the given molecules [[1]](https://mipt.ru/education/chair/chemistry/upload/646/praktikum-arpgsr1gywq.pdf). 2. HF: Hydrogen fluoride (HF) has a longer bond length and lower bond energy compared to HCl. 3. HBr: Hydrogen bromide (HBr) has a longer bond length and lower bond energy compared to HF. 4. HI: Hydrogen iodide (HI) has the longest bond length and lowest bond energy among the given molecules.

b) BCl3, BeCl2, CCl4

The molecules BCl3, BeCl2, and CCl4 can be arranged in order of increasing bond length and bond energy as follows:

1. BeCl2: Beryllium chloride (BeCl2) has the shortest bond length and highest bond energy among the given molecules. 2. BCl3: Boron trichloride (BCl3) has a longer bond length and lower bond energy compared to BeCl2. 3. CCl4: Carbon tetrachloride (CCl4) has the longest bond length and lowest bond energy among the given molecules.

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