Question

Диоксид нецветного металла MO2 содержит 36,8% кислорода. Определить металл и рассчитать его относительную атомную массу. Помогите пж!СРОЧНО НАДО!!!

Answer 1

M(RO2) = 32 г/моль : 0,368 = 87 г/моль
M(R) = 87 г/моль - 32 г/моль = 55 г/моль
R - Mn (марганец)

Answer 2

Identification of the Metal and Calculation of its Relative Atomic Mass

To identify the metal in the compound MO2 and calculate its relative atomic mass, we need to use the given information that the compound contains 36.8% oxygen.

1. Determine the percentage of the other element in the compound: - Since the compound contains 36.8% oxygen, the remaining percentage must be the metal. - Subtracting 36.8% from 100% gives us 63.2% for the metal.

2. Determine the possible metals: - To identify the metal, we need to consider elements that can form a compound with oxygen in a 1:2 ratio (MO2). - Some common metals that can form such compounds include magnesium (Mg), calcium (Ca), strontium (Sr), and barium (Ba).

3. Calculate the relative atomic mass of each possible metal: - To calculate the relative atomic mass, we need to consider the atomic masses of the elements and their respective percentages in the compound. - We can use the periodic table to find the atomic masses of the elements.

Let's calculate the relative atomic masses for each possible metal:

- Magnesium (Mg): - Atomic mass of magnesium (Mg) = 24.31 g/mol. - Percentage of magnesium in MO2 = 63.2%. - Relative atomic mass of magnesium (Mg) = (24.31 g/mol) * (63.2/100) = 15.37 g/mol.

- Calcium (Ca): - Atomic mass of calcium (Ca) = 40.08 g/mol. - Percentage of calcium in MO2 = 63.2%. - Relative atomic mass of calcium (Ca) = (40.08 g/mol) * (63.2/100) = 25.34 g/mol.

- Strontium (Sr): - Atomic mass of strontium (Sr) = 87.62 g/mol. - Percentage of strontium in MO2 = 63.2%. - Relative atomic mass of strontium (Sr) = (87.62 g/mol) * (63.2/100) = 55.35 g/mol.

- Barium (Ba): - Atomic mass of barium (Ba) = 137.33 g/mol. - Percentage of barium in MO2 = 63.2%. - Relative atomic mass of barium (Ba) = (137.33 g/mol) * (63.2/100) = 86.81 g/mol.

Based on the calculations above, the relative atomic masses for each possible metal are as follows:

- Magnesium (Mg): 15.37 g/mol - Calcium (Ca): 25.34 g/mol - Strontium (Sr): 55.35 g/mol - Barium (Ba): 86.81 g/mol

Therefore, the metal in the compound MO2 could be magnesium (Mg), calcium (Ca), strontium (Sr), or barium (Ba), depending on further experimental evidence or additional information.

Please note that the relative atomic masses calculated above are approximate values and may vary slightly depending on the atomic masses used and the accuracy of the given percentages.

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