Question

Какова масса атомов хлора смеси ,содержащей AlCl3 и ICl7 хим. количеством соответственно 1.35 и 0.14 моль. 2)Рассчитайте массу Al2S3, в которой общее число атомов такое же , как и атомов фосфора в навеске Ca3P2 массой 9,828 г. Если знаете, как решить хоть что-то из этого, пишите! Даю много баллов!

Answer 1

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Answer 2

Mass of Chlorine Atoms in a Mixture of AlCl3 and ICl7

To calculate the mass of chlorine atoms in a mixture containing AlCl3 and ICl7, we need to determine the number of moles of each compound and then use the molar mass of chlorine to calculate the mass.

1. Calculate the number of moles of AlCl3 and ICl7: - AlCl3: 1.35 moles - ICl7: 0.14 moles

2. Determine the molar mass of chlorine (Cl): - The molar mass of Cl is approximately 35.45 g/mol [[1]].

3. Calculate the mass of chlorine atoms in the mixture: - Mass of chlorine atoms = (moles of AlCl3 x molar mass of Cl) + (moles of ICl7 x molar mass of Cl) - Mass of chlorine atoms = (1.35 moles x 35.45 g/mol) + (0.14 moles x 35.45 g/mol)

Let's calculate the mass of chlorine atoms in the mixture:

Mass of chlorine atoms = (1.35 moles x 35.45 g/mol) + (0.14 moles x 35.45 g/mol)
Mass of chlorine atoms = 47.8575 g + 4.967 g
Mass of chlorine atoms = 52.8245 g

Therefore, the mass of chlorine atoms in the mixture containing AlCl3 and ICl7 is approximately 52.8245 grams.

Mass of Al2S3 with the Same Number of Atoms as Phosphorus in Ca3P2

To calculate the mass of Al2S3 with the same number of atoms as phosphorus in Ca3P2, we need to determine the number of phosphorus atoms in Ca3P2 and then use the molar mass of Al2S3 to calculate the mass.

1. Determine the number of phosphorus atoms in Ca3P2: - The formula of Ca3P2 indicates that there are 2 phosphorus atoms in each Ca3P2 molecule.

2. Calculate the molar mass of Al2S3: - The molar mass of Al2S3 is approximately 150.17 g/mol [[2]].

3. Calculate the mass of Al2S3 with the same number of atoms as phosphorus in Ca3P2: - Mass of Al2S3 = (number of phosphorus atoms in Ca3P2 x molar mass of Al2S3) / 2

Let's calculate the mass of Al2S3 with the same number of atoms as phosphorus in Ca3P2:

Mass of Al2S3 = (number of phosphorus atoms in Ca3P2 x molar mass of Al2S3) / 2
Mass of Al2S3 = (2 x 150.17 g/mol) / 2
Mass of Al2S3 = 150.17 g

Therefore, the mass of Al2S3 with the same number of atoms as phosphorus in Ca3P2 is approximately 150.17 grams.

I hope this helps! Let me know if you have any further questions.