
Сколько литров этилена необходимо взять для получения 32,2г. этилового спирта путём гидратации
этилена при нормальных условиях?

Ответы на вопрос

СН2=СН2. + Н2О. -> СН3-СН2-ОН
n=1 моль n= 1 моль
Vm=22,4 л/моль М = 46 г/моль
V=22,4 л m=46 г
Х л С2Н4. - 32,2 г С2Н6О
22,4 г C2Н4. - 46 г С2Н6О
V( C2H4) = 22,4 * 32,2 / 46 = 15,68 л



Calculating the Amount of Ethylene Needed for Ethanol Production
To calculate the amount of ethylene needed to produce 32.2g of ethanol through the hydration of ethylene at standard conditions, we can use the following information:
1. The molar mass of ethylene (C2H4) is 28.05 g/mol. 2. The molar mass of ethanol (C2H5OH) is 46.07 g/mol.
Using this information, we can calculate the amount of ethylene needed.
Calculation:
The balanced chemical equation for the hydration of ethylene to produce ethanol is:
C2H4 + H2O → C2H5OH
From the equation, we can see that 1 mole of ethylene (C2H4) reacts with 1 mole of water (H2O) to produce 1 mole of ethanol (C2H5OH).
The molar mass of ethylene (C2H4) is 28.05 g/mol, and the molar mass of ethanol (C2H5OH) is 46.07 g/mol.
Given that we want to produce 32.2g of ethanol, we can calculate the amount of ethylene needed as follows:
Step 1: Convert the mass of ethanol to moles using the molar mass of ethanol: - Number of moles of ethanol = Mass of ethanol / Molar mass of ethanol - Number of moles of ethanol = 32.2g / 46.07 g/mol
Step 2: Use the mole ratio from the balanced chemical equation to find the moles of ethylene needed: - Since the mole ratio of ethylene to ethanol is 1:1, the number of moles of ethylene needed is the same as the number of moles of ethanol.
Step 3: Convert the moles of ethylene to liters at standard conditions: - 1 mole of any gas at standard conditions occupies 22.4 liters.
Result:
Using the above steps, the amount of ethylene needed to produce 32.2g of ethanol through the hydration of ethylene at standard conditions is approximately 0.696 moles, which is equivalent to 15.6 liters at standard conditions.


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