Question

Найдите количество натрия прореагировал без остатка с 98 г 50%-ного раствора соляной кислоты сколько литров водорода выделится при этом?

Answer 1

Дано:
m(розчину)=98г.
W(розчину)-50%
HCl
Знайти:
V(H₂↑)
кількість Na

1.Яка маса Натрію у 98 г. розчину?

m(Na)=98×0.5=49г

2.Який об'єм виділиться водню при взаємодії 49г. Натрію з Хлоридною кислотою.
  49г                         Х л  
 2Na+ 2HCl= 2NaCl+ H₂↑
σ= 2 моль                σ=1 моль
m= 23г                     V= 22.4 л

Х = ( 49 × 22,4 ) / 23 = 47,72 л

Answer 2

Calculating Sodium Reacted with Hydrochloric Acid

To calculate the amount of sodium that reacted with the 50% hydrochloric acid solution, we can use the following chemical equation:

2Na + 2HCl → 2NaCl + H2

According to the equation, 2 moles of hydrochloric acid react with 2 moles of sodium to produce 1 mole of hydrogen gas.

Given: - Mass of 50% hydrochloric acid solution = 98 g - Concentration of the hydrochloric acid solution = 50%

Using the molar mass of HCl (hydrochloric acid) and the concentration of the solution, we can calculate the moles of HCl present in the solution.

The molar mass of HCl is approximately 36.46 g/mol.

The concentration of the 50% hydrochloric acid solution means that it contains 50 g of HCl per 100 g of solution.

Let's calculate the moles of HCl in the given mass of the solution.

Moles of HCl = (Mass of HCl / Molar mass of HCl) = (98 g * 0.50) / 36.46 g/mol

Moles of HCl = 0.672 mol According to the balanced chemical equation, 2 moles of HCl react with 2 moles of sodium to produce 1 mole of hydrogen gas.

So, the moles of sodium that reacted with the HCl can be calculated as:

Moles of Na = Moles of HCl = 0.672 mol

Volume of Hydrogen Gas Produced

The volume of hydrogen gas produced can be calculated using the ideal gas law:

PV = nRT

Where: - P = pressure - V = volume - n = number of moles - R = ideal gas constant - T = temperature

Assuming standard temperature and pressure (STP), which is 0°C and 1 atm, the molar volume of an ideal gas is 22.4 L/mol.

Given: - Moles of hydrogen gas produced = 0.672 mol

Using the molar volume of an ideal gas at STP, we can calculate the volume of hydrogen gas produced:

Volume of hydrogen gas = Moles of hydrogen gas * Molar volume at STP

Volume of hydrogen gas = 0.672 mol * 22.4 L/mol

Volume of hydrogen gas = 15.04 L Therefore, when 98 g of 50% hydrochloric acid solution reacts with sodium, approximately 15.04 liters of hydrogen gas will be produced.