
Бчисліть, який об’єм займає сірководень масою 340 г


Ответы на вопрос

n=m/M
n=340/ 34=10 моль
2. Знаходимо об'єм сірководню
n= V/Vm
V=n*Vm
V=10*22.4=224 л H2S



Calculating the Volume of Hydrogen Sulfide with a Mass of 340g
To calculate the volume of hydrogen sulfide (H2S) with a mass of 340g, we can use the ideal gas law equation, which relates the pressure, volume, amount of substance, and temperature of a gas. The ideal gas law equation is given by:
PV = nRT
Where: - P = pressure - V = volume - n = amount of substance (in moles) - R = ideal gas constant - T = temperature
We can rearrange the ideal gas law equation to solve for volume (V):
V = (nRT) / P
To find the volume of hydrogen sulfide with a mass of 340g, we need to convert the mass to moles using the molar mass of hydrogen sulfide.
Molar Mass of Hydrogen Sulfide (H2S)
The molar mass of hydrogen sulfide (H2S) can be calculated by adding the atomic masses of the elements in the compound.The atomic masses are: - Hydrogen (H): 1.008 g/mol - Sulfur (S): 32.06 g/mol
Using these atomic masses, we can calculate the molar mass of hydrogen sulfide:
Molar mass of H2S = 2(1.008 g/mol) + 32.06 g/mol = 34.086 g/mol
Calculating Moles of Hydrogen Sulfide
To find the moles of hydrogen sulfide in 340g, we can use the following formula:moles = mass / molar mass
Substituting the given mass of 340g and the molar mass of hydrogen sulfide, we get:
moles = 340g / 34.086 g/mol ≈ 9.967 moles
Ideal Gas Law Calculation
Now that we have the moles of hydrogen sulfide, we can use the ideal gas law equation to calculate the volume. Assuming standard temperature and pressure (STP), where the temperature is 273.15 K and the pressure is 1 atm, we can use the ideal gas constant (R) as 0.0821 L·atm/(K·mol).Substituting the values into the ideal gas law equation:
V = (9.967 moles) * (0.0821 L·atm/(K·mol)) * (273.15 K) / (1 atm) ≈ 221.6 L
Therefore, the volume of hydrogen sulfide with a mass of 340g at standard temperature and pressure (STP) is approximately 221.6 liters.


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