Question

расставить коэффициенты в схемах химических реакций:AI+CI=AICI3 CaO+HCI=CaCI2+H2O Mg+HCI=MgCI2+H2 Fe(OH)3=Fe2O3+H2O KNO3=KNO2+O2 NO+O2=NO2 Fe+ O2=Fe2O3 HgO=Hg+O2

Answer 1

2AI+3CI2=2AICI3 
CaO+2HCI=CaCI2+H2O
Mg+2HCI=MgCI2+H2
2Fe(OH)3=Fe2O3+3H2O
2KNO3=2KNO2+O2 
 2NO+O2=2NO2
4Fe+ 3O2=2Fe2O3
2HgO=2Hg+O2

Answer 2

Balancing Chemical Equations

To balance the chemical equations provided, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here are the balanced equations:

1. AI + 3CI = AICI3 2. CaO + 2HCI = CaCI2 + H2O 3. Mg + 2HCI = MgCI2 + H2 4. 2Fe(OH)3 = Fe2O3 + 3H2O 5. 2KNO3 = 2KNO2 + O2 6. 2NO + O2 = 2NO2 7. 4Fe + 3O2 = 2Fe2O3 8. 2HgO = 2Hg + O2

Let's go through each equation and explain the balancing process:

1. AI + 3CI = AICI3 - To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides. - In this case, we have 1 atom of AI and 3 atoms of CI on the left side, so we need to put a coefficient of 3 in front of AI to balance the equation. - The balanced equation is: 3AI + 9CI = AICI3.

2. CaO + 2HCI = CaCI2 + H2O - We have 1 atom of Ca, 1 atom of O, 2 atoms of H, and 1 atom of Cl on the left side. - To balance the equation, we need to put a coefficient of 2 in front of HCI to balance the number of H atoms. - The balanced equation is: CaO + 2HCI = CaCI2 + H2O.

3. Mg + 2HCI = MgCI2 + H2 - We have 1 atom of Mg, 2 atoms of H, and 1 atom of Cl on the left side. - To balance the equation, we need to put a coefficient of 2 in front of HCI to balance the number of H atoms. - The balanced equation is: Mg + 2HCI = MgCI2 + H2.

4. 2Fe(OH)3 = Fe2O3 + 3H2O - We have 2 atoms of Fe, 6 atoms of H, and 6 atoms of O on the left side. - To balance the equation, we need to put a coefficient of 2 in front of Fe2O3 to balance the number of Fe atoms. - The balanced equation is: 2Fe(OH)3 = Fe2O3 + 3H2O.

5. 2KNO3 = 2KNO2 + O2 - We have 2 atoms of K, 2 atoms of N, and 6 atoms of O on the left side. - To balance the equation, we need to put a coefficient of 2 in front of KNO2 to balance the number of K and N atoms. - The balanced equation is: 2KNO3 = 2KNO2 + O2.

6. 2NO + O2 = 2NO2 - We have 2 atoms of N and 3 atoms of O on the left side. - To balance the equation, we need to put a coefficient of 2 in front of NO2 to balance the number of N atoms. - The balanced equation is: 2NO + O2 = 2NO2.

7. 4Fe + 3O2 = 2Fe2O3 - We have 4 atoms of Fe and 6 atoms of O on the left side. - To balance the equation, we need to put a coefficient of 2 in front of Fe2O3 to balance the number of Fe atoms. - The balanced equation is: 4Fe + 3O2 = 2Fe2O3.

8. 2HgO = 2Hg + O2 - We have 2 atoms of Hg and 2 atoms of O on the left side. - To balance the equation, we need to put a coefficient of 2 in front of Hg to balance the number of Hg atoms. - The balanced equation is: 2HgO = 2Hg + O2.

Please let me know if you have any further questions!