Вопрос задан 14.08.2018 в 20:35. Предмет Химия. Спрашивает Бакытов Бахтияр.

Срочно! рассчитайте какой объем газа выделится при термическом разложении 50г caso3

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Отвечает Зинченко Зейнал.
CaSO₃  =  CaO + SO₂

по уравнению реакции
V(SO₂)/V₀ = m(CaSO₃)/M(CaSO₃)

объем сернистого газа
V(SO₂)=V₀(CaSO₃)/M(CaSO₃)

V(SO₂)=22,4л/моль*50г/120г/моль=9,33 л

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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of Gas Volume Released during Thermal Decomposition of 50g of CaSO3

To calculate the volume of gas released during the thermal decomposition of 50g of CaSO3, we need to know the molar mass of CaSO3 and the balanced chemical equation for its decomposition.

The molar mass of CaSO3 can be calculated by adding up the atomic masses of its constituent elements: calcium (Ca), sulfur (S), and oxygen (O). According to the periodic table, the atomic masses of these elements are approximately:

- Calcium (Ca): 40.08 g/mol - Sulfur (S): 32.07 g/mol - Oxygen (O): 16.00 g/mol

Therefore, the molar mass of CaSO3 is:

Molar mass of CaSO3 = (1 * Ca) + (1 * S) + (3 * O) = (1 * 40.08 g/mol) + (1 * 32.07 g/mol) + (3 * 16.00 g/mol) = 136.23 g/mol

Now, let's look at the balanced chemical equation for the thermal decomposition of CaSO3:

2CaSO3(s) → 2CaO(s) + 2SO2(g) + O2(g)

According to the balanced equation, for every 2 moles of CaSO3 decomposed, 2 moles of SO2 gas are released. Therefore, the molar ratio between CaSO3 and SO2 is 1:1.

To calculate the moles of CaSO3 in 50g, we can use the following formula:

Moles of CaSO3 = Mass of CaSO3 / Molar mass of CaSO3 = 50g / 136.23 g/mol

Now, we can calculate the moles of SO2 gas released:

Moles of SO2 = Moles of CaSO3

Finally, to calculate the volume of gas released, we need to use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas (assumed to be constant) - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant (0.0821 L·atm/(mol·K)) - T is the temperature in Kelvin

Since we don't have the pressure and temperature values, we cannot calculate the exact volume of gas released. However, we can calculate the volume of gas released at standard temperature and pressure (STP), which is defined as 1 atmosphere of pressure and 273.15 Kelvin (0 degrees Celsius).

At STP, 1 mole of any ideal gas occupies approximately 22.4 liters. Therefore, the volume of gas released at STP can be calculated as follows:

Volume of gas released at STP = Moles of SO2 * 22.4 L/mol

Please note that this calculation assumes that the reaction goes to completion and that the gas behaves ideally.

Please provide the pressure and temperature values if you need a more accurate calculation.

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