Question

Объём водорода (н.у) ,который выделится при взаимодействии с разбавленной серной кислотой 11,2 г железа в соответствие с уравнением реакции Fe+H2SO4=FeSO4+H2

Answer 1

 11,2 г                                    V=?

  Fe  +   H2SO4   = FeSO4 + H2

n=1 моль                              n=1 моль

М= 56 г/моль                         Vm = 22,4 л/моль

m= 56 г                                   V= 22,4 л

11,2 г Fe         -      X л Н2

56 г Fe          -       22,4 л Н2

V(H2) = 11,2 * 22,4/ 56 = 4,48 л

Answer 2

Reaction and Calculation

The reaction between iron and sulfuric acid can be represented by the equation:

Fe + H2SO4 → FeSO4 + H2

To calculate the volume of hydrogen gas produced when 11.2g of iron reacts with dilute sulfuric acid, we can use the stoichiometry of the reaction and the ideal gas law.

The molar mass of iron (Fe) is approximately 55.85 g/mol The balanced chemical equation shows that 1 mole of iron reacts with 1 mole of hydrogen gas. The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol.

Using this information, we can calculate the volume of hydrogen gas produced.

Calculation Steps

1. Calculate the number of moles of iron. 2. Use the stoichiometry of the reaction to find the number of moles of hydrogen gas produced. 3. Apply the ideal gas law to find the volume of hydrogen gas at STP.

Step 1: Calculate Moles of Iron

The number of moles of iron can be calculated using the formula:

moles = mass / molar mass

Substitute the given mass of iron (11.2g) and the molar mass of iron (55.85 g/mol) into the formula to find the moles of iron.

Step 2: Stoichiometry of the Reaction

From the balanced chemical equation, we know that 1 mole of iron produces 1 mole of hydrogen gas.

Step 3: Apply Ideal Gas Law

At STP, 1 mole of any gas occupies 22.4 L. Using the ideal gas law, we can calculate the volume of hydrogen gas produced.

Result

By following these steps, you can calculate the volume of hydrogen gas produced when 11.2g of iron reacts with dilute sulfuric acid.