Question

Вычисли, сколько литров (н.у.) водорода могут прореагировать с 0,06 моль серы.

Answer 1

S + H2 = H2S
n(H2) = n(S) = 0.06 моль
V(H2) = 0.06 моль * 22,4 л/моль = 1,344 л

Answer 2

Calculating the Volume of Hydrogen Reacting with Sulfur

To calculate the volume of hydrogen gas (at standard conditions) that can react with 0.06 moles of sulfur, we can use the balanced chemical equation for the reaction between hydrogen and sulfur.

The balanced chemical equation for the reaction is: H2 + S → H2S

From the balanced equation, we can see that 1 mole of sulfur reacts with 1 mole of hydrogen to produce 2 moles of hydrogen sulfide.

Given: - Moles of sulfur (S) = 0.06 moles

We need to find the volume of hydrogen gas (H2) that can react with this amount of sulfur.

Using the ideal gas law, we can calculate the volume of hydrogen gas: PV = nRT

Where: - P = pressure (at standard conditions, pressure is 1 atm) - V = volume - n = moles - R = ideal gas constant (0.0821 L·atm/mol·K) - T = temperature (at standard conditions, temperature is 273 K)

We can rearrange the ideal gas law to solve for volume: V = (nRT) / P

Given: - n = moles of hydrogen gas - R = 0.0821 L·atm/mol·K - T = 273 K - P = 1 atm

Let's calculate the volume of hydrogen gas that can react with 0.06 moles of sulfur.

Using the balanced chemical equation, 1 mole of sulfur reacts with 1 mole of hydrogen, so 0.06 moles of sulfur will react with 0.06 moles of hydrogen.

Now, we can calculate the volume of hydrogen gas using the ideal gas law formula.

V = (0.06 moles * 0.0821 L·atm/mol·K * 273 K) / 1 atm

V = 1.58 L

Therefore, 1.58 liters of hydrogen gas (at standard conditions) can react with 0.06 moles of sulfur.