Question

Что получится CH3-CH2-CHBr-CH3 + NaOH (водний розчин)?

Answer 1

CH3-CH2-CHBr-CH3 + NaOH (водний розчин)=СH3-CH2-CH(OH)-CH3 (бутанол-2)+NaBr

Answer 2

Reaction of CH3-CH2-CHBr-CH3 with NaOH (aqueous solution)

When CH3-CH2-CHBr-CH3 reacts with NaOH in an aqueous solution, it undergoes an elimination reaction known as the dehydrohalogenation reaction. This reaction results in the formation of an alkene and sodium bromide.

The reaction can be represented as follows:

CH3-CH2-CHBr-CH3 + NaOH → CH2=CH-CH3 + NaBr + H2O

The sodium hydroxide (NaOH) acts as a base and abstracts a proton (H+) from the β-carbon adjacent to the bromine atom. This leads to the formation of a carbanion, which then eliminates a molecule of hydrogen bromide (HBr) to form the alkene.

This reaction is a type of elimination reaction known as a beta-elimination, specifically an E2 (bimolecular elimination) reaction, where the elimination of HBr and deprotonation occur simultaneously.

The resulting alkene, in this case, CH2=CH-CH3, is an unsaturated hydrocarbon with a double bond between the second and third carbon atoms.

The sodium bromide (NaBr) and water (H2O) are the byproducts of this reaction.