Question

Какая масса раствора соляной кислоты с массовой долей 10% потребуется для растворения 36 г магния?

Answer 1

Не уверена, что правильно

Answer 2

Calculating the Mass of Hydrochloric Acid Solution Needed to Dissolve 36g of Magnesium

To calculate the mass of a 10% hydrochloric acid solution needed to dissolve 36g of magnesium, we can use the following steps:

1. Determine the Chemical Equation for the Reaction: - The chemical equation for the reaction between magnesium and hydrochloric acid is: ``` Mg + 2HCl -> MgCl2 + H2 ```

2. Calculate the Amount of Hydrochloric Acid Needed: - The stoichiometry of the reaction shows that 1 mole of magnesium reacts with 2 moles of hydrochloric acid. - The molar mass of magnesium is 24.305 g/mol. - Using the molar ratio, we can calculate the amount of hydrochloric acid needed to react with 36g of magnesium.

3. Determine the Mass of the 10% Hydrochloric Acid Solution Needed: - Once we know the amount of hydrochloric acid needed, we can calculate the mass of the 10% solution required.

Calculation Steps

1. Calculate the moles of magnesium: - The moles of magnesium can be calculated using the formula: ``` moles = mass / molar mass ``` - Substituting the values, we get: ``` moles = 36g / 24.305 g/mol ```

2. Calculate the moles of hydrochloric acid: - From the balanced chemical equation, we know that 1 mole of magnesium reacts with 2 moles of hydrochloric acid. - Therefore, the moles of hydrochloric acid needed will be twice the moles of magnesium.

3. Calculate the mass of the 10% hydrochloric acid solution needed: - The mass of the 10% hydrochloric acid solution needed can be calculated using the formula: ``` mass = (volume of solution) * (density of solution) ```

Result

The mass of the 10% hydrochloric acid solution needed to dissolve 36g of magnesium can be calculated using the steps outlined above.

Let's proceed with the calculations.