Question

Помогите пожалуйста решить. Рассчитать сколько серебра выделится в реакции серебряного зеркала из 17,6 г ацетальдегида.

Answer 1

CH3-CHO + Ag2O (t,NH4OH)= CH3-COOH + 2Ag(осадок)
v(CH3-CHO)=m/M=17,6/44=0,4 моль
v(Ag)=2v(CH3-CHO)=0,8 моль
m(Ag)=v*M=0,8*108=86.4 г.
Ответ:86,4 г.

Answer 2

Calculating the Amount of Silver Deposited in the Silver Mirror Reaction

To calculate the amount of silver that will be deposited in the silver mirror reaction from 17.6 g of acetaldehyde, we can use the balanced chemical equation for the reaction and stoichiometry.

The balanced chemical equation for the silver mirror reaction is: 1. C10H8O + 4Ag(NH3)2OH → 10Ag + 4NH4OH + H2O

From the balanced chemical equation, we can see that 1 mole of acetaldehyde (C10H8O) reacts with 4 moles of silver diamine complex (Ag(NH3)2OH) to produce 10 moles of silver (Ag).

Calculation Steps

1. Convert the given mass of acetaldehyde to moles. 2. Use the mole ratio from the balanced chemical equation to find the moles of silver deposited. 3. Convert the moles of silver to grams.

Calculation

1. Converting the given mass of acetaldehyde to moles: - The molar mass of acetaldehyde (C10H8O) is approximately 44.053 grams/mol. - Number of moles = Mass / Molar mass - Number of moles = 17.6 g / 44.053 g/mol - Number of moles ≈ 0.3998 mol

2. Using the mole ratio from the balanced chemical equation: - From the balanced chemical equation, 1 mole of acetaldehyde reacts with 4 moles of silver diamine complex to produce 10 moles of silver. - Moles of silver = Moles of acetaldehyde × (10 moles of Ag / 1 mole of C10H8O) - Moles of silver ≈ 0.3998 mol × 10 - Moles of silver ≈ 3.998 mol

3. Converting the moles of silver to grams: - The molar mass of silver (Ag) is approximately 107.87 grams/mol. - Mass of silver = Moles of silver × Molar mass - Mass of silver ≈ 3.998 mol × 107.87 g/mol - Mass of silver ≈ 431.2 g

Result

The amount of silver deposited in the reaction from 17.6 g of acetaldehyde is approximately 431.2 grams.

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