
Сколько кг этанола получается при брожении глюкозы, если выделилось 11,2 м3 CO2?


Ответы на вопрос




x=11.2*92/44.8=23 кг



Ethanol Production from Glucose Fermentation
To calculate the amount of ethanol produced from the fermentation of glucose, we can use the stoichiometry of the reaction. The balanced chemical equation for the fermentation of glucose to ethanol and carbon dioxide is:
C6H12O6 → 2 C2H5OH + 2 CO2
Given that 11.2 m^3 of CO2 is produced, we can calculate the amount of ethanol produced using the stoichiometric ratio from the balanced equation.
The molar ratio of CO2 to ethanol in the reaction is 2:2, which simplifies to 1:1. This means that for every mole of CO2 produced, one mole of ethanol is also produced.
Using this information, we can calculate the amount of ethanol produced.
Calculation
The molar volume of a gas at standard temperature and pressure (STP) is approximately 22.4 L/mol. Converting 11.2 m^3 to liters: 11.2 m^3 * 1000 L/m^3 = 11200 LNow, we can calculate the moles of CO2 produced: 11200 L / 22.4 L/mol = 500 moles of CO2
Since the molar ratio of CO2 to ethanol is 1:1, the moles of ethanol produced will also be 500.
Conclusion
Therefore, when 11.2 m^3 of CO2 is produced during the fermentation of glucose, approximately 500 moles of ethanol are also produced.


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