Question

1) K + I2 = KI 2) KI = K + I2 3) KI + CL2 = KCL + I2 4) K + S = KaS 5) C + Cl2 = CCl4 помогите пожалуйста, 9 класс оксилительно- восстановительные реакции

Answer 1

Нигма в помощь там набери все эти реакции она выдаст тебе ответы 
со всеми подробностями

Answer 2

1) KI2 = K + I2 The reaction equation shows that potassium iodide (KI) reacts with iodine (I2) to form potassium (K) and iodine (I2). [[1]]

2) KI = K + I2 This equation represents the decomposition of potassium iodide (KI) into potassium (K) and iodine (I2). [[2]]

3) KI + Cl2 = KCl + I2 In this reaction, potassium iodide (KI) reacts with chlorine (Cl2) to produce potassium chloride (KCl) and iodine (I2). [[3]]

4) K + S = KaS This equation represents the reaction between potassium (K) and sulfur (S) to form potassium sulfide (KaS). [[4]]

5) C + Cl2 = CCl4 The reaction equation shows that carbon (C) reacts with chlorine (Cl2) to produce carbon tetrachloride (CCl4). [[5]]

These equations represent various oxidation-reduction reactions involving different substances. Oxidation-reduction reactions, also known as redox reactions, involve the transfer of electrons between reactants. In these reactions, one reactant is oxidized (loses electrons) while the other is reduced (gains electrons). The substances that undergo oxidation are called reducing agents, while those that undergo reduction are called oxidizing agents.

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